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juin [17]
3 years ago
13

Find the interquartile range for the box plot below.*

Mathematics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

Step-by-step explanation:

u should do those step and i think u will find the answer

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nexus9112 [7]

Answer:

x=6

Step-by-step explanation:

h(x) = -( x-2)^2 +16

We want when h(x) = 0

0 = -( x-2)^2 +16

Subtract 16 from each side

-16  = -( x-2)^2 +16-16

-16 = -( x-2)^2

Divide by -1

16= ( x-2)^2

Take the square root of each side

±sqrt(16) = sqrt(( x-2)^2 )

±4 = x-2

Add 2 to each sdie

2 ±4 = x-2+2

2+4 = x     2-4 =x

6 =x           -2 =x

since time cannot be negative

x=6

4 0
3 years ago
The coordinates of the vertices of​ quadrilateral ABCD​ are A(−4, −1), B(−1, 2), C(5, 1), and D(1, −3).
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Answer:

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Step-by-step explanation:

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3 years ago
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What is the side length, in inches, of the pets
tatiyna

Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of 16x2 – 40x + 25 square inches. What is the side length, in inches, of the pet shop sign?

Answer:

the length of the sign is 4x-5 inches

Step-by-step explanation:

Given

Area of the square of design = 16x^{2} -40x+25

First we find the roots of equation 16x^{2} -40x+25=0

The roots of the quadratic equation ax^{2} +bx^{2} +c=0 are given by

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a=16, b=-40, c=25

x=\frac{40\pm\sqrt{(-40)^2-4\times 16\times 25}}{2\times 16}

x=\frac{40\pm\sqrt{1600-1600}}{32}

x=\frac{40\pm\sqrt{0}}{32}

x=\frac{40}{32}

x=\frac{5}{4}

4x=5\\4x-5=0

That is, the factors of the polynomial 16x^{2} -40x+25 are 4x-5 and 4x-5.

So, Area of the square design = 16x^{2} -40x+25 = (4x-5)^{2}

Area of a square = Length^2

Thus, the length of the sign is 4x-5 inches

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What is the inverse function of h(x)=-3/5x+1/2?​
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Answer:

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Step-by-step explanation:

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