All categories

2 years ago

Find the interquartile range for the box plot below.*

Mathematics

1 answer:

alexgriva [62]2 years ago

6 0

Answer:

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

Step-by-step explanation:

u should do those step and i think u will find the answer

You might be interested in

What is the distance between M(9, −5) and N(−11, 10)?

lesya692 [45]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{25 \: units}}}}}$

Step-by-step explanation:

Let M ( 9 , -5 ) be ( x₁ , y₁ ) and N ( - 11 , 10 ) be ( x₂ , y₂ )

Finding the distance between these points

$\boxed{ \sf{distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {( - 11 - 9)}^{2} + {(10 - ( - 5))}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {( - 20)}^{2} + {(10 + 5)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {( - 20)}^{2} + {(15)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{400 + 225}}}$

$\longrightarrow{ \sf{ \sqrt{625}}}$

$\longrightarrow{ \sf{ \sqrt{ {(25)}^{2} } }}$

$\longrightarrow{ \sf{25 \: units}}$

Hope I helped!

Best regards! :D

7 0

2 years ago

3 Which of these is equivalent to 4 81 64 44 12

jek_recluse [69]

The answer is 44. ! Your welcome

8 0

2 years ago

Cameron made 1 loaf of bread. His family ate 4/6 of the loaf of bread. How much of the loaf of bread remains?/

nlexa [21]

Answer:

2/6

Step-by-step explanation:

because 4/6 is eaten so that means 2/6 is left to eat

7 0

2 years ago

Read 2 more answers

Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th

creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

$C=A+B=(a_1+b_1,a_2+b_2)$

And its magnitude is:

$C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9$

Where

$a_1=Asinx$

$a_2=Acosx$

$b_1=Bsin(x+90)$

$b_2=Bcos(x+90)$

Using the properties of the sum of two angles in the sin and cosine:

$b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx$

$b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx$

Sustituying in the magnitud of the sum

$C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9$

$C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9$

$C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}$

$C=\sqrt{A^2+B^2} =9$

Solving for B

$A^2+B^2 =9^2$

$B^2 =9^2-A^2$

Sustituying the value of the magnitud of A

$B^2=81-5^2=81-25=56$

$B= 7. 4833$

8 0

2 years ago

Pleaseeee helpppp answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!

Fed [463]

Answer:

z=44

Step-by-step explanation:

One way to go about this with the given angles is to use the alternate interior angles theorem to find the full measure of ∠C and ∠A. Then, use the same theorem to set ∠BDA as 52°. Subtract all the angle measures from 360 (because the sum of the interior angles of a quadrilateral is = 360 degrees). Then divide the result by 2.

360-84-84-52-52=88

=88/2

=44

So z=44°

5 0

2 years ago