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skelet666 [1.2K]
3 years ago
5

Please Help ASAP!!! Would you be able to prove this is a right triangle or would it just be a scalene triangle?

Mathematics
2 answers:
daser333 [38]3 years ago
8 0
Triange ADB is an isosceles triangle being bisected, so Triangle ADE is a right triangle
Dvinal [7]3 years ago
3 0
It is a right Right Triangle because, they have two equal sides.
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For all of the Following use the function LaTeX: P\left(x\right)\:=\:\left(x+3\right)^2+2 . My original vertex is
PolarNik [594]

Answer:

A) Q(x) = (x + 3)² + 5, and the vertex is (-3, 5)

B) R(x) = (x - 3)² + 2, and the vertex is (3, 2)

C) S(x) = (x - 1)² - 5, and the vertex is (1, -5)

Step-by-step explanation:

The given function is P(x) = (x + 3)² + 2

The given function is a parabolic function in vertex form, f(x) = a·(x - h)² + k, and vertex, (h, k)

By comparison, the vertex of the function P(x) = (x + 3)² + 2 is (-3, 2)

A) A function f(x) translated α units UP gives

f(x) (translated α units UP) → f(x) + α

A translation of the function 3 units UP is given by adding 3 to the given function as follows;

Q(x) = P(x) + 3

∴ Q(x) = (x + 3)² + 2 + 3 = (x + 3)² + 5

Q(x) = (x + 3)² + 5, and the vertex by comparison to f(x) = a·(x - h)² + k, and vertex, (h, k) is (-3, 5)

B) A function f(x) translated <em>b</em> units RIGHT gives;

f(x) translated <em>b</em> units right → f(x - b)

∴ P(x) = (x + 3)² + 2 translated 6 units RIGHT gives;

P(x) = (x + 3)² + 2 (translated 6 units RIGHT) → R(x) = (x + 3 - 6)² + 2 = (x - 3)² + 2

R(x) = (x - 3)² + 2, and the vertex by comparison is (3, 2)

C) A function translated α units DOWN and <em>b</em> units RIGHT is given as follows;

f(x) \ translated \ by\  \dbinom{b}{a} \rightarrow f(x - b) - a

Therefore, the given function, P(x) = (x + 3)² + 2, translated 7 units DOWN and 4 units RIGHT gives;

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow P(x - 4) - 7 = S(x)

S(x) = P(x - 4) - 7 = (x + 3 - 4)² + 2 - 7 = (x - 1)² - 5

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow (x - 1)^2 - 5= S(x)

S(x) = (x - 1)² - 5, and the vertex by comparison is (1, -5)

7 0
3 years ago
What is the compatible of 192 -87
valkas [14]
The compatible is
190 - 90 =
6 0
3 years ago
[PLEASE HELP! 49 POINTS PER ANSWER!]
blagie [28]

A negative exponent for powers of 10 represent numbers between 0 and 1.

5 0
3 years ago
PQ is tangent to OR at point P. Find mZQ.<br> A. 17°<br> B. 27°<br> C. 63°<br> D. 73°
mamaluj [8]

Answer:

A

Step-by-step explanation:

The angle between the tangent PQ and the radius RP at the point of contact P is 90°

The sum of the 3 angles in Δ PQR = 180° , thus

∠ Q = 180° - (90 + 73)° = 180° - 163° = 17° → A

6 0
2 years ago
50+10+23×61×80 please help mee!!​
Cloud [144]

Answer:

112300

Step-by-step explanation:

50+10+23*61*80

=60+23*61*80

=60+112240

=112300

The answer 112300, hope this helped :)

4 0
2 years ago
Read 2 more answers
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