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GREYUIT [131]
3 years ago
6

The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers

Mathematics
1 answer:
Pavel [41]3 years ago
7 0

The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers

two consecutive even integers: n, n+2

next two consecutive even integers n+4, n+6

n+(n+2) >= 7+1/2(n+4 +n+6)

combine like terms

2n+2 >= 7 +1/2(2n+10)

distribute 1/2

2n+2 >= 7+n+5

2n+2>= n+12

subtract n from each side

n+2>= 12

subtract 2 from each side

n>10

4 integers : 10, 12 ,14, 16

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Hello!!

════ ⋆★⋆ ════

\mathbb{A~N~S~W~E~R~:}

= r · 2

➡ \Huge \sf \mathbb \color{}\underline{\colorbox{ANSWER~WITH~EXPLANATION ~!}{}}

\mathfrak{apply~the~fraction~rule:  }   a \frac{b}{c} =\frac{a~. ~b }{c}

\mathfrak{apply~rule:  }  a · 1 = a

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=\frac{r~.~4}{2}

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So, your answer will be is :

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\color{}{Hope\:it\:helps. ..}

#LearnWithBrainly

\mathbb{A~N~S~W~E~R~:}

\mathfrak{Jace}

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