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alexandr402 [8]
3 years ago
10

Maggie colors a figure in the shape of a trapezoid.The trapezoid is 6 inches tall.The bases are 4.5 inches and 8 inches.What is

the area of the figure that Maggie colored?
Mathematics
1 answer:
Tcecarenko [31]3 years ago
5 0
The answer for this is 37.5. I can't show the work because i searched it up on Google.
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NEED ANSWERED ASAP!!!!!!!
Igoryamba

Answer:

5.25 is the lenght of the arc AB.

Step-by-step explanation:

First, since we are told the answer should be expressed in radians, we need to convert the arc angle into radians, we do that by multiplying the angle by π and dividing by 180.

60° * π/180 = 1.05rad

Now, there is a simple formula to calculate the arc lenght, A = Ф*r, where:

A = arc lenght

Ф = arc angle (60°=1.05rad)

r = radius (5cm)

A = 1.05*5cm

A = 5.25cm

5 0
3 years ago
Use distance formula d=√(X2 – X1 )2 + (X2 – X1 )2, calculate the distance r from the origin to the point r (-2, √5).
lesya692 [45]
d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} \\d = \sqrt{(\sqrt{5} - (-2))^{2} + (\sqrt{5} - (-2))^{2}} \\d = \sqrt{(\sqrt{5} + 2)^{2} + (\sqrt{5} + 2)^{2}} \\d = \sqrt{(4 + 4\sqrt{5} + 5) + (4v + 4\sqrt{5} + 5)} \\d = \sqrt{0 + 0} \\d = \sqrt{0} \\d = 0
7 0
3 years ago
HELP<br> Given: ABCD is a parallelogram and AC bisects BD.<br> Prove: AC bisects
34kurt

2) ABCD is a rhombus (a parallelogram with perpendicular diagonals is a rhombus)

3) \overline{AC} bisects \angle BCD (diagonals of a rhombus bisect the angles from which they are drawn)

8 0
2 years ago
Simplify.<br><br> 184.10<br> x 16<br> -----------
Mariulka [41]

Answer:

2.9456k is the correct answer

8 0
3 years ago
Read 2 more answers
A rectangle has an area of 100 cm he base of the rectangle is 25 cm.
Brrunno [24]
The correct answer is 4
100=25/X
X=4

6 0
4 years ago
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