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alexandr402 [8]
3 years ago
10

Maggie colors a figure in the shape of a trapezoid.The trapezoid is 6 inches tall.The bases are 4.5 inches and 8 inches.What is

the area of the figure that Maggie colored?
Mathematics
1 answer:
Tcecarenko [31]3 years ago
5 0
The answer for this is 37.5. I can't show the work because i searched it up on Google.
You might be interested in
Consider the function f(x)= 2/5x-4
Gre4nikov [31]

Answer: a) \frac{5}{2}x+10=f^{-1}(x)=g(x)

Step-by-step explanation:

Since we have given that

f(x)=\frac{2}{5}x-4

a.) Find the inverse of f(x) and name it g(x).

Let f(x) = y

So, it becomes

y=\frac{2}{5}x-4

Switching x to y , we get

x=\frac{2}{5}y-4

5x=2y-20\\\\5x+20=2y\\\\\frac{5x+20}{2}=y\\\\\frac{5}{2}x+10=y\\\\\frac{5}{2}x+10=f^{-1}(x)=g(x)

b) . Use composition to show that f(x) and g(x) are inverses of each other.

\mathrm{For}\:f=\frac{2}{5}x-4\:\\\\\mathrm{substitute}\:x\:\mathrm{with}\:g\left(x\right)=\frac{5}{2}x+10\\\\=\frac{2}{5}\left(\frac{5}{2}x+10\right)-4\\\\=x

Similarly,

\mathrm{g\left(x\right)=\frac{5}{2}x+10,\:f\left(x\right)=\frac{2}{5}x-4,\:g\left(x\right)\circ \:f\left(x\right)}\\\\\mathrm{For}\:g=\frac{5}{2}x+10\:\mathrm{substitute}\:x\:\mathrm{with}\:f\left(x\right)=\frac{2}{5}x-4\\\\=\frac{5}{2}\left(\frac{2}{5}x-4\right)+10\\\\=x

so, both are inverses of each other.

c) Draw the graphs of f(x) and g(x) on the same coordinate plane.

As shown below in the graph , Since for inverse function we need an axis of symmetry i.e. y=x

And both f(x) and g(x) are symmetry to y=x.

∴ f(x) and g(x) are inverses of each other.


5 0
3 years ago
Homework please help its over due​
xxMikexx [17]

Step-by-step explanation:

TRIANGLE 1

c = 2√5

= 2 × √5

= √4 × √5

= √20

a = 2

b = ?

b² = c² - a²

= √20² - 2²

= 20² - 4

= 400 - 4

= 396

b = √396

= √36 × √11

= 6 × √11

= 6 √11

TRIAGLE 2

a = 12

b = 6√11

= √396

c = ?

c² = a² + b²

= 12² + √396

= 144 + √396²

= 144 + 396

c = √540

= √36 × √15

= 6 × √15

= 6 √15

Sorry if i wrong. Im beginner in USA server

4 0
3 years ago
Assuming the amount of money college students spend on text books each semester is symmetrical with a mean of 500 and a standard
TiliK225 [7]

16% percent of the students paid MORE than Jane.

The mean(μ) of money spent on textbooks is 500

The standard deviation(σ) of money spent on textbooks is 50

Money paid by Jane for her books is $550

We will use this formula,

Ζ=x-μ/σ

To find: the percentage of students paid MORE than Jane for the textbooks

P(X > 550)=?

Solution:

P(X > 550)=1-P(X≤550)

=1-P(Ζ≤\frac{550-500}{50} )

=1-P(Ζ≤ 1)

=1-0.8413

=0.1587

≈16%

Therefore, 16% percent (approx) of the students paid MORE than Jane.

Learn more about mean and standard deviation here brainly.com/question/4388715

#SPJ4

3 0
2 years ago
PLEASE HELP !!!!!!<br><br> find the missing number on the number line
Bogdan [553]
8 because the line is going up by 1 as seen from 4 and 6
4 0
2 years ago
Read 2 more answers
For a luxury doughnut producer the average selling price is £2. The average variable cost is 40% of the selling price and its fi
Cerrena [4.2K]

Answer:

620

Step-by-step explanation:

selling 400 doughnuts means selling 800 £ worth of doughnuts. 800 x 0.4 ( to find 40 percent) = 320, + 300 because the the fixed cost = 620. :)

6 0
3 years ago
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