Answer:
Step-by-step explanation:
Let d be the common difference.
a₁₀ = a₁ + (10-1)d
13 = -5 + 9d
d = 2
The ratio is - 6:12
(6 boys, 12 girls)
You can use the Pythagorean Theorem to find the length of the third side AB (Identified as "x" in the figure attached in the problem), which says that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs:
a² = b²+c²
As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:
b = √(a²-c²) b = √(10²-4²) b = 9.16
With these values, we can find the hypotenuse in the triangle "B": x = √b²+c² x = √(9.16)²+(4)² x = 10
2x + 7y + 3x - 4y
Collect all the like terms:
2x + 3x = 5x
7y - 4y = 3y
And you end up with 5x + 3y as your final answer :)
This is the answer ,you should first do the multiplication then the sum.