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3 years ago

The point Q(-1, 4) is reflected over the line x = -2. What are the coordinates of the resulting point, Q’?

Mathematics

1 answer:

IgorC [24]3 years ago

8 0

-1 -4 is the awnser to the question

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Step-by-step explanation:

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3 years ago

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Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.

sergij07 [2.7K]

Answer:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

Step-by-step explanation:

Given

$8x^{-10}y^6 - 2x^2y^{-8}$

Required

Simplify

Rewrite as:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}$

Take LCM

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6*y^8 - 2x^2 * x^{10}}{x^{10}y^8}$

Apply law of indices

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

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3 years ago

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Arte-miy333 [17]

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3 years ago

HELP PLS! A boat is heading towards a lighthouse, whose beacon-light is 102 feet above the water. From point AA, the boat’s crew

KatRina [158]

Answer:

Distance from point AA to point BB = 189.3 feet

Step-by-step explanation:

Let the distance from point AA to the base of the lighthouse be represented by x, and the distance from point BB to the base of the lighthouse be represented by y. So that;

distance from point AA to point BB = x - y

To determine the value of x, applying the required trigonometric function;

Tan θ = $\frac{opposite}{sdjacent}$