The <em>expanded</em> expressions are shown below:
- (x + 1)² = x² + 2 · x + 1
- (x - 3)² = x² - 6 · x + 9
- (x + 4)² = x² + 8 · x + 16
- (x - 1/2)² = x² - x + 1/4
- 3 · (x - 5)² = 3 · (x² - 10 · x + 25) = 3 · x² - 30 · x + 75
- (1/2) · (x - 2)² = (1/2) · (x² - 4 · x + 4) = (1/2) · x² - 2 · x + 2
<h3>How to expand perfect square trinomials</h3>
<em>Perfect square</em> trinomials are polynomials of grade 2 with the form (a + b)² = a² + 2 · a · b + b². In this case, we have to expand six perfect square trinomials:
a) (x + 1)² = x² + 2 · x + 1
b) (x - 3)² = x² - 6 · x + 9
c) (x + 4)² = x² + 8 · x + 16
d) (x - 1/2)² = x² - x + 1/4
e) 3 · (x - 5)² = 3 · (x² - 10 · x + 25) = 3 · x² - 30 · x + 75
f) (1/2) · (x - 2)² = (1/2) · (x² - 4 · x + 4) = (1/2) · x² - 2 · x + 2
To learn more on perfect square trinomials: brainly.com/question/385286
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Answer: x = -11 ∠FGK = 30° ∠KGH = 150°
<u>Step-by-step explanation:</u>
∠FGK + ∠KGH = ∠FGH <em>Segment Addition Postulate</em>
x + 41 + x + 161 = 180 <em>Substitution</em>
2x + 202 = 180 <em> Simplify (added like terms)</em>
2x = -22 <em>Subtraction Property of Equality</em>
x = -11 <em>Division Property of Equality</em>
∠FGK = x + 41 = (-11) + 41 = 30
∠KGH = x + 161 = (-11) + 161 = 150
Answer:
D, A, B, C
Step-by-step explanation:
D is the smallest number, then it goes A, then B and C is the highest as it is a positive number.
hope this helps!
<span>This really works well with wax paper. It is transparent and it leaves a visible white line on the crease. For the perpendicular bisector of a line segment, fold the endpoints of the line segment onto each other. The crease is the perpendicular bisector. This of course also gives you the midpoint, because that is where the perpendicular bisector intersects the line segment. For an angle bisector, put the crease through the vertex of the angle and lay the sides of the angle over top of each other. The crease is the angle bisecto
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