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kykrilka [37]
3 years ago
12

Could anyone help me on this please

Mathematics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

yes? what is the question?

Step-by-step explanation:

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What is the value of the (x,y) point (3,1.5) in the function M = 4x + 2y?
Feliz [49]
I hope this helps you

4 0
3 years ago
Read 2 more answers
The fives in which number represent 500 and 50,000?
german

Answer:

251,576

Step-by-step explanation:

first look at the them thousands place, see that it has a "5" in it, and also look for the "5" in the hundred's place

That number has 5 in both the ten-thousands, and the hundreds place and the rest don't have both.

(Hope that helps explain the brain teaser)

7 0
3 years ago
What is the slope of a line perpendicular to the line y = 2x + 5? Type a numerical answer in the space provided. Do not type spa
Rama09 [41]

Answer:

  -1/2

Step-by-step explanation:

The slope of the given line is the coefficient of x, which is 2.

The slope of the perpendicular line is the negative reciprocal of that:

  -1/2

4 0
2 years ago
Solve for x. x - 2(2 - 3/2 x) = 2(4 - x) + 1
STALIN [3.7K]

Answer:

x = 13/6

Step-by-step explanation:

We are the following expression;

       x - 2(2 - (3/2)*x) = 2(4 - x) + 1

       x - (4 - 3*x) = 8 - 2*x + 1

       x - 4 + 3*x = 8 - 2*x + 1

         4*x + 2*x = 9 + 4

             6*x = 13

              x = 13/6

8 0
3 years ago
Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

3 0
3 years ago
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