Answer:
6.84 ≤ x ≤ 37.39
Step-by-step explanation:
we have
-----> equation A
we know that
The company wants to keep its profits at or above $225,000,
so
-----> inequality B
Remember that P(x) is in thousands of dollars
Solve the system by graphing
using a graphing tool
The solution is the interval [6.78,39.22]
see the attached figure
therefore
A reasonable constraint for the model is
6.84 ≤ x ≤ 37.39
Answer:
y = -1/2x - 1
Step-by-step explanation:
We can use the point-slope form of the equation:
y-y1 = m(x-x1)
Where the given y1 = -2, x1 = 2, and m = -1/2. This yields:
y - (-2) = -1/2(x - 2)
y + 2 = -1/2x + 1
y = -1/2x +1 - 2
y = -1/2x - 1
The Mid - point of the line segment is at coordinates - M(- 7.5, 0.5)
We have two coordinate points - A(- 10, 2) and B(- 5, -1)
We have to find the midpoint of this line AB.
<h3>What is Mid - Point Theorem?</h3>
It states that a line with endpoint coordinates as -
and
has its mid - point at the coordinates -

According to question, we have -
First coordinate Point -
= (- 10, 2)
Second coordinate Point -
= (- 5, - 1)
Using the Mid - Point formula, we get -
=

Hence, the Mid - point of the line segment is at coordinates -
M(- 7.5, 0.5)
To solve more questions on Mid - points, visit the link below -
brainly.com/question/25377004
#SPJ1
Answer:
64.65% probability of at least one injury commuting to work in the next 20 years
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Each day:
Bikes to work with probability 0.4.
If he bikes to work, 0.1 injuries per year.
Walks to work with probability 0.6.
If he walks to work, 0.02 injuries per year.
20 years.
So

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

We want
. Then

In which



64.65% probability of at least one injury commuting to work in the next 20 years