Ask question

Ask question

All categories

2 years ago

14

What is 3.5 divided by 7

2 answers:

max2010maxim [7]2 years ago

6 0

Answer:

1/2 or 0.5

Step-by-step explanation:

....

sladkih [1.3K]2 years ago

5 0

Answer:

0.5

Step-by-step explanation:

You might be interested in

Three rational numbers between 5/31 and 6/31

Ludmilka [50]

Answer:

$\dfrac{26}{155}$ , $\dfrac{27}{155}$ , and $\dfrac{28}{155}$ .

Step-by-step explanation:

What is a rational number? By definition, a rational number can be represented as the fraction of two integers.

The goal is to find three fractions in the form $\dfrac{p}{q}$ between $\dfrac{5}{31}$ and $\dfrac{6}{31}$ .

$\dfrac{5}{31} < \dfrac{p}{q} < \dfrac{6}{31}$ .

At this moment, there doesn't seems to be a number that could fit. The question is asking for three of these numbers. Multiple the numerator and the denominator by a number greater than three (e.g., five) to obtain

$\dfrac{25}{155} < \dfrac{p}{q} < \dfrac{30}{155}$ .

Since $p$ and $q$ can be any integers, let $q = 155$ .

$\dfrac{25}{155} < \dfrac{p}{155} < \dfrac{30}{155}$ .

$\implies 25 < p < 30$ .

Possible values of $p$ are 26, 27, and 28. That corresponds to the fractions

$\dfrac{26}{155}$ , $\dfrac{27}{155}$ , and $\dfrac{28}{155}$ .

These are all rational numbers for they are fractions of integers.

6 0

3 years ago

Un avión dispone de 24 asientos en clase A y de 62 asientos en clase B cuya venta supone un total de $15,390. Sin embargo, sólo

Talja [164]

Answer:HOLA I Do not speack spanish

Step-by-step explanation:

6 0

3 years ago

Fifteen girls left a mixed group of boys and girls. There remained two boys for each girl. After this, 45 boys leave the group,

statuscvo [17]

Sorry i cant answer this way too hard for me

5 0

2 years ago

If f(x)=x^3-12x^2+35x-24f(x)=x 3 −12x 2 +35x−24 and f(8)=0f(8)=0, then find all of the zeros of f(x)f(x) algebraically.

Neporo4naja [7]

Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

<em></em>

Step-by-step explanation:

Given

$f(x)=x^3-12x^2+35x-24$

$f(8) = 0$

Required

Find all zeros of the f(x)

If $f(8) = 0$ then:

$x = 8$

And $x - 8$ is a factor

Divide f(x) by x - 8

$\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}$

Expand the numerator

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}$

Rewrite as:

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}$

Expand

$\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}$

$\frac{f(x)}{x - 8} = (x - 1)(x - 3)$

Multiply both sides by x - 8

$f(x) = (x - 1)(x - 3)(x - 8)$

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>

7 0

2 years ago

4:5 12:? 32:40 ?:55 ?:95<br> The answer in blanks

posledela

Hakkakwksoosjanakskwkwkwkmskskwkw

6 0

2 years ago

Read 2 more answers