A horse canters away from its trainer in a straight line, moving 37 m away in 9.1 s. It then turns abruptly and gallops halfway
back in 1.8 s . Calculate its average speed for the entire trip.
Express your answer using two significant figures.
Calculate its average velocity for the entire trip, using "away from the trainer" as the positive direction.
Express your answer using two significant figures.
Express your answer using two significant figures.
Calculate its average velocity for the entire trip, using "away from the trainer" as the positive direction.
Express your answer using two significant figures.
1 answer:
Answer:
Average velocity = 1.69 m/s
Average speed = 5.09 m/s
Explanation:
Given that
Horse cover 37 m in 9.1 sec and 18.5 m in 1.8 sec.
As we know that
Average velocity = Displacement / Total time
Average speed = Total distance / Total time
Average velocity:
Average velocity = Displacement / Total time
Total displacement = 37 - 18.5 = 18.5 m
Total time = 9.1 + 1.8 =10.9 s
Average velocity = Displacement / Total time
Average velocity = 18.5 / 10.9
Average velocity = 1.69 m/s
Average speed:
Average speed = Total distance/ Total time
Total distance = 37 + 18.5 = 55.5 m
Total time = 9.1 + 1.8 =10.9 s
Average speed = Total distance/ Total time
Average speed = 55.5 / 10.9
Average speed = 5.09 m/s
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a is its acceleration
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is the mass of the wagon + the brother, so the acceleration of the wagon and the brother is