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iris [78.8K]
2 years ago
11

An artillery shell has a mass of 55 kg. The shell is fired from the muzzle of the gun

Physics
1 answer:
Evgen [1.6K]2 years ago
4 0

The average force on the shell while it is in the gun barrel is 10,869,833.33N.

<h3>HOW TO CALCULATE FORCE?</h3>

Force applied on an object can be calculated by multiplying the mass of the object by its acceleration.

However, the acceleration needs to be calculated by using the following equation:

v² - u² = 2as

Where;

  • v = final velocity
  • u = initial velocity
  • a = acceleration
  • s = distance

770² - 0² = 2 (a)(1.5)

592900 = 3a

a = 197633.3m/s²

Force = 55kg × 197633.3m/s²

Force = 10,869,833.33N

Therefore, the average force on the shell while it is in the gun barrel is 10,869,833.33N.

Learn more about force at: brainly.com/question/26115859

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7 0
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The thermosphere has _____ air pressure than the mesosphere.<br><br> more<br> less<br> equal
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The electricity that is delivered to our homes from regional generating stations moves over transmission lines that are _____.
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Magnetic resonance imaging needs a magnetic field strength of 1.5 T. The solenoid is 1.8 m long and 75 cm in diameter. It is tig
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I=2.27 x 10 to the 3rd power A
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3 years ago
A monatomic ideal gas initially fills a container of volume V = 0.25 m3 at an initial pressure of P = 250 kPa and temperature T
Murrr4er [49]

Answer:

number of moles = 27.34 moles

the temperature of gas after it undergoes the isobaric expansion = 605 K

Explanation:

Given that:

V = 0.25 m³

P = 250 kPa

T = 275 K

V₂ = 0.55 m³

P₂ = 760 kPa

a)

Using ideal gas equation ; PV = nRT

n = \frac{PV}{RT}\\\\n =  \frac{250*10^3*0.25}{8.314*275}\\\\n = \frac{62500}{2286.35}\\\\n = 27.34 \ moles

b) To calculate the temperature of gas after it undergoes the isobaric expansion; we have:

  1. \frac{V_1}{T_1}= \frac{V_2}{T_2}\\\\\frac{0.25}{275}= \frac{0.55}{T_2}\\\\T_2=\frac{0.55*275}{0.25}\\\\T_2 = 605 K

4 0
4 years ago
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