50POINTS! What is the escape velocity for lunar module? Lunar module mass 15,200 kg radius of moon 1.74x106m, mass of moon 7.34x
2 answers:
Answer:
2.73 km/s
Explanation:
The escape velocity of an object in the gravitational field of the moon is (on the surface of the planet)
where
is the gravitational constant
is the mass of the Moon
is the radius of the Moon
As we can see, the escape velocity does not depend on the mass of the lunar module.
Substituting the numbers into the formula, we find
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Answer:
I = 11.26 mA
Explanation:
given,
V = 0.7 V length = 80 m
diameter = 0.2 mm = 0.02 cm
radius = 0.01 × 10⁻² m
ρ for gold wire = 2.44 × 10⁻⁸ ohm-m at 20 °C
A = cross sectional area = π r² = π (0.01 × 10⁻² )²
= 31.4× 10⁻⁹ m²
R = 62.165 Ω
I = 11.26 mA
Answer:
the weight of the object decreases when it is taken from the Earth to the Moon
Explanation:
The weight of an object is defined as the product of the mass of the object with the acceleration due to gravity of the Planet.
where,
W = weight of the object
m = mass of the object
g = acceleration due to gravity on the planet
The mass of an object remains constant everywhere in the universe. Therefore, the weight is directly proportional to the value of acceleration due to gravity.
The value of acceleration due to gravity on the Moon is lesser than its value on the Earth.
<u>Hence, the weight of the object decreases when it is taken from the Earth to the Moon </u>