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3 years ago

8

50POINTS! What is the escape velocity for lunar module? Lunar module mass 15,200 kg radius of moon 1.74x106m, mass of moon 7.34x

1022kg

2 answers:

Airida [17]3 years ago

7 0

Answer:

2.73 km/s

Explanation:

The escape velocity of an object in the gravitational field of the moon is (on the surface of the planet)

$v=\sqrt{\frac{2GM}{r}}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$M=7.34\cdot 10^{22} kg$ is the mass of the Moon

$r=1.74\cdot 10^6 m$ is the radius of the Moon

As we can see, the escape velocity does not depend on the mass of the lunar module.

Substituting the numbers into the formula, we find

$v=\sqrt{\frac{2(6.67\cdot 10^{-11})(7.34\cdot 10^{22}kg)}{(1.74\cdot 10^6 m)}}=2732 m/s=2.73 km/s$

mash [69]3 years ago

6 0

Answer:

2.73 km/s

Explanation:

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Answer

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