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iris [78.8K]
2 years ago
15

Calculate the amount of centripetal force it takes for a softball pitcher to rotate a ball with a velocity of 3m/s if the ball w

eight. 12 kg and her arm is. 65 meters long quizzez
Physics
1 answer:
hram777 [196]2 years ago
8 0

The amount of centripetal force it takes for a softball pitcher to rotate a ball will be 1.661 N.

<h3>What is centripetal force?</h3>

The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.

The centripetal force is found as;

\rm F_C=  \frac{mv^2}{r} \\\\ \rm F_C=  \frac{.12 \times (3)^2}{.65} \\\\ F_C=1.661 \ N

Hence,the amount of centripetal force it takes for a softball pitcher to rotate a ball will be 1.661 N.

To learn more about the centripetal force, refer to the link;

brainly.com/question/10596517

#SPJ4

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Answer:

1.24

Explanation:

The resistivity of copper\rho_1=2.65\times 10^{-8}\ \Omega-m

The resistivity of Aluminum,\rho_2=1.72\times 10^{-8}\ \Omega-m

The wires have same resistance per unit length.

The resistance of a wire is given by :

R=\rho \dfrac{l}{A}\\\\R=\rho \dfrac{l}{\pi (\dfrac{d}{2})^2}\\\\\dfrac{R}{l}=\rho \dfrac{1}{\pi (\dfrac{d}{2})^2}

According to given condition,

\rho_1 \dfrac{1}{\pi (\dfrac{d_1}{2})^2}=\rho_2 \dfrac{1}{\pi (\dfrac{d_2}{2})^2}\\\\\rho_1 \dfrac{1}{{d_1}^2}=\rho_2 \dfrac{1}{{d_2}^2}\\\\(\dfrac{d_2}{d_1})^2=\dfrac{\rho_1}{\rho_2}\\\\\dfrac{d_2}{d_1}=\sqrt{\dfrac{\rho_1}{\rho_2}}\\\\\dfrac{d_2}{d_1}=\sqrt{\dfrac{2.65\times 10^{-8}}{1.72\times 10^{-8}}}\\\\=1.24

So, the required ratio of the diameter of Aluminum to Copper wire is 1.24.

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Question 7 of 25
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