Which identifies a machine that converts mechanical energy into electrical energy?

1 answer:

8 0

The answer is the option c. generator. Generator is a machine that converts mechanical energy into electricity. The way it is made is because the mechanical movement may be transformed in rotation of magnets placed inside a coiled wire, and this induces the movement of electrons through the coiled wire. As you know electricity is the flow of electrons.

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A pendulum is made from a thin cylindrical rod pivoted at the end. It has a length of 0.30 m and radius 0.001 m. It swings up to

Art [367]

Answer:

Maximum angle is $23.91^{\circ}$ rad

Explanation:

As per the question:

length of the pendulum, L = 0.30 m

Radius of the pendulum, R = 0.001 m

Angular speed at the bottom, $\omega = 2.9\ rad/s$

Now,

To calculate the maximum angle, $\theta_{m}$ :

For the pendulum, the moment of inertia, I = $\frac{ML^{2}}{3}$

Now, using the principle of the conservation of energy:

Kinetic energy = Potential energy

$\frac{1}{2}\times I\omega^{2} = mgh$

where

h = $\frac{L}{2}(1 - cos\theta_{m})$

Thus

$\frac{1}{2}\times \frac{mL^{2}}{3}\times \omega^{2} = m\times 9.8\times \frac{L}{2}(1 - cos\theta_{m})$

$1 - cos\theta_{m} = \frac{0.3\times 2.9^{2}}{3\times 9.8}$

$theta_{m} = cos^{- 1}(0.914) = 23.91^{\circ}$

6 0

3 years ago

You want the current amplitude through a 0.450 mH inductor (part of the circuitry for a radio receiver) to be 1.50 mA when a sin

Kobotan [32]

Answer:

Explanation:

The formula for calculating the voltage across an inductor is expressed as

$V_l = IX_l\\\\Since\ X_l = 2\pi fL\\V_l = I(2\pi fL)$

Given parameters

current amplitude I = 1.50mA = 1.5*10⁻³A

inductance L = 0.450mH = 0.450*10⁻³H

Voltage across the inductor $V_l$ = 13.0V

Required

frequency f

Substituting the given parametres into the formula, we have;

$V_l = I(2\pi fL)\\\\13 = 1.50*10^{-3}(2*3.14*f*0.450*10^{-3})\\\\13 = 4.239*10^{-6}f\\\\f = \frac{13}{4.239*10^{-6}} \\\\f = 3,066,761 Hertz\\\\f = 3.067MHz$