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sveta [45]
3 years ago
14

Solve for x. x^3=1/27

Mathematics
1 answer:
Tatiana [17]3 years ago
7 0
<em>1/3 is answer. Hope it helps

</em>
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How many cubic meters of material are there in a conical pile of dirt that has radius 9 meters and height 6 meters 6 meters​? Us
alisha [4.7K]
To find the volume of a cone, you use the formula \pi  r^{2}  \frac{h}{3}.
Radius squared would be 36 in our case and 36 times 3.14 is 113.04. 6 thirds is  also two, so multiply that by two and you would get 113.04 x 2 = 226.08. So, your answer would be 226.08 cubic meters of dirt.
7 0
3 years ago
Identify the slope and the y-intercept in the equation y = -3/4x + 3. Please make sure to say which is the slope and which is th
Liula [17]

Answer:

the y -intercpt is the 3

the slope is -3/4

Step-by-step explanation:

this is because the 3 is the starting point on the y-axis and the slope is -3/4 because you are going down 3 to the right 4 ---hope this helps

5 0
4 years ago
Read 2 more answers
PLEASE HELP!!!
quester [9]

Answer:

18

Step-by-step explanation:

because the number of people that can swim will be about quarter out of hundred

7 0
3 years ago
A ball is thrown directly up in the air from a height of 5 feet with an initial velocity of 60 ft/s. Ignoring air resistance, ho
Mice21 [21]

Answer:

3.8 seconds

Step-by-step explanation:

Given equation

h= -16t^2 + 60t + 5

When the ball hits the ground then height is 0

So we replace h with 0 and solve for t

0= -16t^2 + 60t + 5

a= -16 , b= 60 and c= 5

Apply quadratic formula to solve for t

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

=\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}

=\frac{-60+-28\sqrt{5}}{-32}

=\frac{4(-15+-7\sqrt{5})}{-32}

=\frac{(-15+-7\sqrt{5})}{-8}

Now make two fractions and solve for x

t= -\frac{7\sqrt{5}-15}{8}=-0.0815

t= \frac{7\sqrt{5}+15}{8}=3.83

So answer is 3.8 seconds


4 0
3 years ago
Select the function that’s represented in the graph
vesna_86 [32]

Answer:

D.

Step-by-step explanation:

you can use a graphing calculator to graph the equation and match it with the picture.

6 0
3 years ago
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