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Shalnov [3]
2 years ago
10

shawn is shoppping for a rug for his dinning room. the rectangular sug he likes measures 5 feat by 7 feet. what is the area of t

he rug?
Mathematics
1 answer:
Ganezh [65]2 years ago
3 0

Answer:

<u>35 square feet</u>

Step-by-step explanation:

Area of the rug :

  • Length x width
  • 7 x 5
  • <u>35 square feet</u>
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Find all solutions in the interval [0,2π) of the equation.
Sauron [17]

Step-by-step explanation:

2sin(x)cos(x) - sin(x) + 2cos(x)-1= 0

<=> sinx( 2cosx -1) + ( 2cosx -1) =0

<=> (sinx +1) + ( 2cosx-1)=0

<=> sinx=-1 or cosx= 1/2

+) sinx=1 => x= pi/2 + k×2pi

+)cosx=1/2 => x= pi/3+ k×2pi or x=-pi/3 + k×2pi

x€ [0,2pi] => x= pi/2, pi/3.

3 0
3 years ago
What is the equation of (4,10),(6,11) in standard form?​
SIZIF [17.4K]

ANSWER

The standard form is:

x - 2y =  - 16

EXPLANATION

The given line passes through (4,10)and (6,11).

The slope of this line is

m =  \frac{11 - 10}{6 - 4}

m =  \frac{1}{2}

The equation is given by the formula,

y-y_1=m(x-x_1)

We plug in the first point and the slope to get.

y-10= \frac{1}{2} (x-4)

2y - 20 = x - 4

x - 2y  =  - 20 + 4

x - 2y =  - 16

The standard form is

x - 2y =  - 16

7 0
3 years ago
Point C does not lie on line xy. Can point C lie in the same plane as live xy? Explain
uysha [10]

The answer is yes.

A line and a point outside the line define a unique plane. In other words, there is a single plane that contains a line and a point outside the line. If you are given line XY and point C outside the line, there is a single plane containing both line XY and point C. Therefore, line XY and point C must lie in the same plane.

4 0
3 years ago
Joe's father is 15 more than twice Joe's age. How old is Joe's father? Solve algebraically.
dalvyx [7]

Answer:

Joe's father is 45.

Step-by-step explanation:

3x-x+2=4

6 0
3 years ago
Read 2 more answers
Hi, does someone know what this question is looking for?<br> There is no other instructions.
slamgirl [31]

Answer: 3y⁴(y² + 5)(y - 1)(y + 1)

<u>Step-by-step explanation:</u>

 3y⁸ + 12y⁶ - 15y⁴

= 3y⁴(y⁴ + 4y² - 5)

= 3y⁴(y² + 5)(y² - 1)

= 3y⁴(y² + 5)(y - 1)(y + 1)

7 0
3 years ago
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