Question

The length of a rectangle is 3 ft more than twice the width, and the area of the rectangle is 54 ft2. find the dimensions of the rectangle.

Answer 1

A = L * W
A = 54
L = 2W + 3

54 = W(2W + 3)
54 = 2W^2 + 3W
2W^2 + 3W - 54 = 0
(2W - 9)(W + 6) = 0

2W - 9 = 0
2W = 9
W = 9/2
W = 4.5 <== width

W + 6 = 0
W = -6....it wont be this one because it is negative

L = 2W + 3
L = 2(4.5) + 3
L = 9 + 3
L = 12 <==length