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Alika [10]
3 years ago
14

Simplify (7/9a+9/7b)^2-ab

Mathematics
1 answer:
lianna [129]3 years ago
7 0
Ab+49/81a^2+81/49b^2
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How are average I.Q.s related to normal distributions?
Flauer [41]

In USA the average I.Q. is 98 while the top one average I.Q. country is Hong Kong.

But the I.Q. distribution is given by a polinomial graph, few people with extremely low I.Q. 40~70, a lot between 70~100, some between 100~120, few between 120~140 and extremely low 140+

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3 years ago
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Can someone help me ​
Slav-nsk [51]

9514 1404 393

Answer:

  M = 7x² +21

Step-by-step explanation:

Subtract the unwanted terms on the left from both sides.

  (-7x² +6x -16) + M = 6x +5

  M = 6x +5 -(-7x² +6x -16)

  M = 7x² +21 . . . . simplify

5 0
3 years ago
Find the value of x picture attached
aev [14]

Answer:

<em>x = 10</em>

Step-by-step explanation:

These angles are <em>same side interior angles</em>.

This means that (11x + 10) + (10x - 40) = 180

Solve for x:

11x + 10 + 10x - 40 = 180

21x - 30 = 180

      +30     +30

21x = 210

/21      /21

<em>x = 10</em>

3 0
3 years ago
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
3 years ago
HELP ME PLSSSSSSSSSSSSSSSSS<br>​
9966 [12]

4 \times 10 {}^{6}  + 7 \times  {10}^{5}  + 2 \times  {10}^{4}  + 3 \times  {10}^{3}   + 9 \times  {10}^{2}  + 1 \times  {10}^{1}  + 0 \times   {10}^{0}

7 0
3 years ago
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