Answer:
Option (4)
Step-by-step explanation:
Perimeter of a polygon is the sum of measures of all sides of the polygon.
From the picture attached,
Distance run by Dallas = Perimeter of the ground
= 48 + 50 + 9 + 30 + 30 + 30 + 9 + 50
= 256 yards
Total warm up run by Dallas = 256 yards
Therefore, Option (4) will be the correct option.
Answer:
18 terms
Step-by-step explanation:
The first given sequence has first term a1=2 and common difference d=5. Its explicit formula is ...
an = 2 +5(n -1) = 5n -3
We want the n-th term of this sequence to be the same as the n-th term of the sequence defined by ...
an = 4n +15
We can find n that makes this true by setting the 'an' values equal:
an = an
5n -3 = 4n +15
n = 18 . . . . . . . . . . add 3-4n
The number of terms in each sequence is 18.
_____
<em>Additional comment</em>
The last term in each sequence is 87.
Answer:
A. x=6 B. x=4.5 C. x-35 D. x=13
Step-by-step explanation:
For A and B, divide the numbers you have. For C and D, multiply the numbers you have.
Answer:
Length = 7 Width = 2
Step-by-step explanation:
L = Length
W = Width
L=9w-11
2L+2W=18
2(9W-11) + 2W = 18
18W - 22 +2W = 18
20W -22 = 18
20W = 40
W = 2
L = 9(2)-11
L=18-11
L=7
A
Volume of the Cylinder
Givens
H = 60 yards.
Diameter = 20 yards
pi = 3.14
Formula
V = pi * r^2 * h
Calculations
r = d/2
r = 32/2
r = 16
V = 3.14 * 16^2 * 60
V = 48230 cubic yards [Cylinder's Volume]
Cone
<em>Formula</em>
V = 1/3 pi r^2 H
<em>Givens</em>
pi = 3.14
r = 16 yards
h = 20 yards
<em>Sub and solve</em>
V = 1/3 3.14 * 16^2 * 20
V = 5359 cubic yards.
<em>Total Volume of the structure</em>
48230 + 5359 = 53589 Cubic Yards
<em>Water Content</em>
The answer to this part requires a proportion.
1 Cubic yard will hold 201.97 gallons.
53589 yd^3 = x
1/201.97 = 53589 /x [ You should get a pretty big answer]
x = 201.87 * 53589
x = 10 819 092 gallons can be held by the tank.
10 819 092 gallons <<<< answer
B
If the height of both the cylinder and the cone remain the same. If the radius doubles in both the cylinder and the cone then the tank will hold 4 times as much.
Total volume before doubling the radius = pi * r^2 h + 1/3 pi r^2 h
New Total Volume = pi * (2*r)^2 h + 1/3 pi * (2r)^2 h
New Total volume = pi * 4r^2 h + 1/3 pi *4 r^2 h
New Total Volume = 4 [pi r^2 h + 1/3 pi r^2 h]
but pi r^2 h + 1/3 pi r^2 h is the total volume before doubling the radius
New volume = 4 original volume. <<<<< answer to part B
