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3 years ago

Im really struggling. please help me

Mathematics

2 answers:

butalik [34]3 years ago

6 0

Answer:

Heya here is your answer

Step-by-step explanation:

a) 3x = 18

x = 18/3

x = 6

b) 2x = 9

x = 4.5

x = 4 1/2 ( in Mixed fraction)

c) x/5 = 7

x = 7 x 5

x = 35

d) x/2 = 6.5

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

X/2 = 6.5 // - 6.5

X/2-6.5 = 0

1/2 X -6.5 = 0 + 6.5

1/2X = 6.5 : 1/2

X = 6.5/1/2

X = 13

Hope this answer satisfies you

Wittaler [7]3 years ago

5 0

Answer:

A. x=6 B. x=4.5 C. x-35 D. x=13

Step-by-step explanation:

For A and B, divide the numbers you have. For C and D, multiply the numbers you have.

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Compute delta y/delta x for the interval [2,5], where y = 4x - 9.

Kamila [148]

We have to compute: Δ y / Δ x.
The interval is [ 2, 5 ] and y = 4 x - 9.
y 1 = 4 · 2 - 9 = 8 - 9 = - 1
y 2 = 4 · 5 - 9 = 20 - 9 = 11
Δ y / Δ x = ( y 2 - y 1 ) / ( x 2 - x 1 ) =
= ( 11 - ( - 1 ) ) / ( 5 - 2 ) = ( 11 + 1 ) / 3 = 12 / 3 = 4
Answer:
Δ y / Δ x = 4

3 0

3 years ago

13/20 as a percent and 7/25 as a percent to no need to show work just need the straight up percent

Ivahew [28]

13/20 = 65%
7/25 = 28%

4 0

2 years ago

A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medica

expeople1 [14]

Answer:

The sample mean is of 1925 calories.

The margin of error is of 75 calories.

The sample standard deviation is of 109.7992 calories.

Step-by-step explanation:

Sample mean:

The sample mean is the mean value of the two bounds of the confidence interval. So

$M = \frac{1850 + 2000}{2} = 1925$

The sample mean is of 1925 calories.

The margin of error

Difference between the bounds and the sample mean. So

2000 - 1925 = 1925 - 1850 = 75 calories.

The margin of error is of 75 calories.

Sample standard deviation:

Here, I am going to expand on the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 18 - 1 = 17

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 17 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 2.898