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3 years ago

A sprinter has a mass of 80 kg and a KE of 4000 J. What is the sprinter’s speed?

Physics

2 answers:

djyliett [7]3 years ago

8 0

There you go.

Hope this helps!

Sladkaya [172]3 years ago

4 0

   Kinetic Energy = (1/2) (mass) (speed)²

   4,000 J = (1/2) (80 kg) (speed)²

Divide each side
by 40 kg : 4,000 J / 40 kg = speed²

100 m²/s² = speed²
Square root
each side:    10 m/s = speed

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Ls -2 a solution of 4x +3= -5?.<br>

torisob [31]

Answer:

yes

Explanation:

Let's solve your equation step-by-step.

4x+3=−5

Step 1: Subtract 3 from both sides.

4x+3−3=−5−3

4x=−8

Step 2: Divide both sides by 4.

4x / 4 = −8 / 4

x=−2

Hope it helps,

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5 0

3 years ago

A ball rolls of buildings that is 100m high calculate the time that it takes for ball to hit the ground

LUCKY_DIMON [66]

Answer:

2as=v2-u2

2000=v2

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V=u+at

44/10=t

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3 years ago

Particles q1, 92, and q3 are in a straight line.

NNADVOKAT [17]

The net force on q₃ will be 17.51 N. The net force is the algebraic sum of the two forces on the pleading q₃

<h3 /><h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The force,by the charge q₁ on the q₃;

$\rm F_{31}} = \frac{Kq_1q_3}{r^2} \\\\ \rm F_{31}} = \frac{9 \times 10^9 \times -28.1 \times 10^{-6}\times \times -47.9 \times 10^{-6}}{(0.600)^2} \\\\ F_{31}} =33.64 \ N$

The force,by the charge q₂ on the q₃;

$\rm F_{32}} = \frac{Kq_2q_3}{r^2} \\\\ \rm F_{32}} = \frac{9 \times 10^9 \times 25.5 \times 10^{-6}\times \times -74.9\times 10^{-6}}{(0.300)^2} \\\\ F_{32}} =-19.09 \ N$

The net force is the sum of the two forces;

$\rm F_{net}=F_{32}+F_{31}\\\\\ \rm F_{net}=36.6-19.9 \\\\ \rm F_{net}=17.51 \ N$

Hence, the net force on q₃ will be 17.51 N.

To learn more about Columb's law, refer to the link;

brainly.com/question/1616890

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2 years ago

23692U = 14456Ba + 89 36Kr + 3n is a

alekssr [168]

I think The answer is c

5 0

3 years ago

a wooden block has a mass of 1.2 kg, a specific heat of 710, and is at a temperature of 25*C. what is the block's final temperat

mash [69]

The final temperature of the block is $27.5^{\circ} C$

Explanation:

The amount of thermal energy Q supplied to a substance is related to the increase in temperature of the substance, $\Delta T$ , according to the equation