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Svetach [21]
3 years ago
6

A sprinter has a mass of 80 kg and a KE of 4000 J. What is the sprinter’s speed?

Physics
2 answers:
djyliett [7]3 years ago
8 0
There you go.

Hope this helps!

Sladkaya [172]3 years ago
4 0

               Kinetic Energy  =  (1/2) (mass) (speed)²

                         4,000 J  =  (1/2) (80 kg) (speed)²    

Divide each side
by  40 kg :            4,000 J / 40 kg  =  speed²

                                    100 m²/s²  =  speed²
Square root
each side:                         10 m/s  =  speed
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A sled and rider (combined mass of 69 kg) finish a downhill run with a speed of 30 m/s, then enter a flat (horizontal) area wher
NARA [144]

Answer:

Distance that sled move while slowing down= 195.65m

Explanation:

Distance traveled by sled after slowing down=S

acceleration at the start= -2.3 m/s2

initial speed u=30m/s

final speed=v

By using the equation

v^{2} =u^{2} +2as\\

Final speed is zero.

Therefore;

0=30^{2} +2*(-2.3)*s\\2*2.3s=30^{2} \\s=30^{2} /(2*2.3)\\s=195.65 m

6 0
3 years ago
A string along which waves can travel is 4.36 m long and has a mass of 222 g. The tension in the string is 60.0 N. What must be
lora16 [44]

Answer:

frequency is 195.467 Hz

Explanation:

given data

length L = 4.36 m

mass m = 222 g = 0.222 kg

tension T = 60 N

amplitude A = 6.43 mm = 6.43 × 10^{-3} m

power P = 54 W

to find out

frequency f

solution

first we find here density of string that is

density ( μ )= m/L ................1

μ = 0.222 / 4.36  

density μ is 0.050 kg/m

and speed of travelling wave

speed v = √(T/μ)       ...............2

speed v = √(60/0.050)

speed v = 34.64 m/s

and we find wavelength by power that is

power = μ×A²×ω²×v  /  2     ....................3

here ω is wavelength put value

54 = ( 0.050 ×(6.43 × 10^{-3})²×ω²× 34.64 )   /  2

0.050 ×(6.43 × 10^{-3})²×ω²× 34.64 = 108

ω² = 108 / 7.160  × 10^{-5}

ω = 1228.16 rad/s

so frequency will be

frequency = ω / 2π

frequency = 1228.16 / 2π

frequency is 195.467 Hz

7 0
4 years ago
Science please help!
Romashka [77]
<span>Inertia is a property of matter
i hope this help</span>
6 0
3 years ago
Read 2 more answers
Prominences and sunspots are both:
Vadim26 [7]

Answer:

C. Influenced by the Sun's electromagnetic field

Explanation:

"Sunspots occur in pairs because each is one side of a loop of the Sun's magnetic field that reaches the Sun's surface. Solar prominences are the plasma loops that connect two sunspots."

8 0
3 years ago
Which of the following events may occur when IR radiation is absorbed?
Vilka [71]

Answer:

c. More intense IR absorption occur for those bonds having greater dipole moment changes with bond lengthening in a vibration.

Explanation:

When the molecules is exposed to the infrared radiation, the sample molecules absorb the radiation of wavelengths (specific to molecule) which causes change in the dipole moment of the sample molecules. The vibrational energy levels of the sample molecules consequently transfer from the ground state to the excited state.  

Frequency of absorption peak is determined by vibrational energy gap.

Intensity of absorption peaks is related to change of dipole moment and possibility of transition of the energy levels.  

Thus, by analyzing infrared spectrum,abundant structure information of the molecule can be known.

Hence, the correct answer to the question is

c. More intense IR absorption occur for those bonds having greater dipole moment changes with bond lengthening in a vibration.

3 0
3 years ago
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