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2 years ago

Calculate the volume of a 45 kg bucket knowing its density which is 2.7 kg/m3 (cubic meters)

1 answer:

6 0

Given: Mass m = 45 Kg: Density ρ = 2.7 Kg/m³

Required: Volume V = ?

Formula: ρ = m/V

V = m/ρ

V = 45 Kg/2.7 Kg/m³

V = 16.67 m³

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Is 5g greater than 20.43 mg

worty [1.4K]

yes that's true 6g is larger

4 0

2 years ago

Read 2 more answers

Answer ?

morpeh [17]

Answer:

2.75 m/s^2

Explanation:

The airplane's acceleration on the runway was 2.75 m/s^2

We can find the acceleration by using the equation: a = (v-u)/t

where a is acceleration, v is final velocity, u is initial velocity, and t is time.

In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1

a = 2.75 m/s^2

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1 year ago

A В C D At which point will an image be formed? ОА Ов Ос OD

Anettt [7]

Answer:

Explanation:

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1 year ago

Which object exerts more gravitational force, object A with a mass of 15 grams and a density of 2g/cm3 or object B with a mass o

puteri [66]

The answer is B.

More mass means more gravitational force.

Hope it helps!

8 0

2 years ago

At the Indianapolis 500, you can measure the speed of cars just by listening to the difference in pitch of the engine noise betw

allsm [11]

To develop this problem it is necessary to apply the concepts related to the Dopler effect.

The equation is defined by

$f_i = f_0 \frac{c}{c+v}$

Where

$f_h$ = Approaching velocities

$f_i$ = Receding velocities

c = Speed of sound

v = Emitter speed

And

$f_h = f_0 \frac{c}{c+v}$

Therefore using the values given we can find the velocity through,

$\frac{f_h}{f_0}=\frac{c-v}{c+v}$

$v = c(\frac{f_h-f_i}{f_h+f_i})$

Assuming the ratio above, we can use any f_h and f_i with the ratio 2.4 to 1

$v = 353(\frac{2.4-1}{2.4+1})$

$v = 145.35m/s$

Therefore the cars goes to 145.3m/s

7 0

2 years ago