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3 years ago

8

Calculate the volume of a 45 kg bucket knowing its density which is 2.7 kg/m3 (cubic meters)

1 answer:

nadya68 [22]3 years ago

6 0

Given: Mass m = 45 Kg: Density ρ = 2.7 Kg/m³

Required: Volume V = ?

Formula: ρ = m/V

V = m/ρ

V = 45 Kg/2.7 Kg/m³

V = 16.67 m³

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A force in the +x-direction with magnitude ????(x) = 18.0 N − (0.530 N/m)x is applied to a 6.00 kg box that is sitting on the ho

fiasKO [112]

Answer:

$v_f=8.17\frac{m}{s}$

Explanation:

First, we calculate the work done by this force after the box traveled 14 m, which is given by:

$W=\int\limits^{x_f}_{x_0} {F(x)} \, dx \\W=\int\limits^{14}_{0} ({18N-0.530\frac{N}{m}x}) \, dx\\W=[(18N)x-(0.530\frac{N}{m})\frac{x^2}{2}]^{14}_{0}\\W=(18N)14m-(0.530\frac{N}{m})\frac{(14m)^2}{2}-(18N)0+(0.530\frac{N}{m})\frac{0^2}{2}\\W=252N\cdot m-52N\cdot m\\W=200N\cdot m$

Since we have a frictionless surface, according to the the work–energy principle, the work done by all forces acting on a particle equals the change in the kinetic energy of the particle, that is:

$W=\Delta K\\W=K_f-K_i\\W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}$

The box is initially at rest, so $v_i=0$ . Solving for $v_f$ :

$v_f=\sqrt{\frac{2W}{m}}\\v_f=\sqrt{\frac{2(200N\cdot m)}{6kg}}\\v_f=\sqrt{66.67\frac{m^2}{s^2}}\\v_f=8.17\frac{m}{s}$

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3 years ago

What is the change in thermal energy E if the coefficent of kinetic friction between the box and floor is .4 , the distance the

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This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

$Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd$

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

$E = (0.4)(38\ N)(17\ m)$

<u>E = 258.4 J</u>

Learn more about friction energy here:

brainly.com/question/1343045?referrer=searchResults

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2 years ago

What is the density of a cube that has a mass of 3.75 g and a volume of 3 mL?

valina [46]

Answer:

$\displaystyle \rho=1.25\ g/ml$

Explanation:

<u>Density </u>

The density of a substance is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

$\displaystyle \rho=\frac{m}{V}$

The cube has a mass of m=3.75 g and a volume of V=3 ml, thus the density is:

$\displaystyle \rho=\frac{3.75\ g}{3\ ml}$

$\boxed{\displaystyle \rho=1.25\ g/ml}$

Since 1 kg=1000 mg and 1 lt = 1000 ml, the density has the same value but with different units:

$\displaystyle \rho=1.25\ kg/l$

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