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Lorico [155]
3 years ago
15

A rectangular block measures 4.1cm by 2.8cm by 2.1cm. calculate its volume given you answer to an appropriate number of signific

ant figures?​
Physics
2 answers:
EleoNora [17]3 years ago
8 0

Answer:

<u>Volume</u><u> </u><u>=</u><u> </u><u>24.108cm</u><u>³</u>

Explanation:

Volume = length × breadth × height

Volume = 4.1 × 2.8 × 2.1

Volume = 24.108

sattari [20]3 years ago
6 0

Answer:

Volume =  24 cm^3

Explanation:

We recall that the volume of the box is calculated via the formula:

Volume = length * height * width

and that in a product, the number of significant figures for the result should coincide with the number of significant figures of the factor that has the least of them.

In this case, all measures have the same number of significant figures: two. so we calculate the product, and then limit the answer value to exactly two significant figures:

Volume = 4.1 cm * 2.8 cm * 2.1 cm = 24.108 cm^3, which must be rounded to two significant figures as: 24 cm^3

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Answer:

charges of the beads is 1.173 ×10^{-15} C

Explanation:

given data

mass = 3.8589 g = 0.003859 kg

spring length = 5 cm = 0.05 m

extend spring x = 1.5747 cm = 0.15747 m

spring's extension = 0.0116 m

to find out

charges of the beads

solution

we know that force is

force = mass × g

force = 0.003859 × 9.8

force = 0.03782 N

so we know  force for mass

force  = -kx

so k = force / x

put here force and x value

k = -0.03782 / 0.1575

k = -0.24 N/m

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force = -kx

force = -0.24 ( 0.0116) = 0.002784 N

so here

total length L = 0.05 + 0.0116 = 0.0616

so charges of the beads = force × L² / ke

charges of the beads = 0.002784 × (0.0616)² / (9 ×10^{9} )

so charges of the beads = 1.173 ×10^{-15} C

3 0
3 years ago
Impact of electricity in the society
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Answer:

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The weight of a box is found to be 30 N. What is the approximate mass of the box?
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The mass of the box would be 30!
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What is the momentum of a 200 kg football player running west at a speed of 8m/s
lutik1710 [3]

Answer:

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Explanation:

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<h3>1600 kgm/s</h3>

Hope this helps you

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