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3 years ago

If a is a positive integer and b is a negative integer, which expression must be positive?

2 answers:

8 0

If A is a positive integer and B is a negative integer, The expression that is positive: =====> Answer NONE OF THEM

A. a - b =====>

B. a + b =====> Zero (0)

C. a • b

D. a / b =====> A and B can take any values, Either Negative or Positive

Answer would be, NONE OF THE ABOVE

Hope that helps: : )

nydimaria [60]3 years ago

4 0

So, let's solve all of them and see:

a - (-b) = a + b ⇒ can be either positive or negative, depending on the numbers

a + (-b) = a - b ⇒ can either be positive or negative, depending on the numbers

a * (-b) = a * (-b) ⇒ negative answer no matter what

a / (-b) = a / (-b) ⇒ negative answer no matter what

So the answer is:

<em>"None of the above"</em>.

Hope it helped,

BioTeacher101

(If you have any questions, feel free to ask them in the comments)

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Solve the systems by the addition method x - 2y = - 4 2x + y = 7

vfiekz [6]

To solve this system of equations by addition, our first goal is to cancel

out one of the variables by adding the two equations together.

However, if we add these two equations together right away, nothing

will cancel so we need to set things up so a variable will cancel.

Notice that we have an 2x in our second equation.

If we had a -2x in our first equation, then the x's would cancel out.

In order to create a -2x in the first equation, we simply

multiply both sides of the first equation by -2.

So we have (-2)(x - 2y) = (-4)(-2) which can be rewritten as -2x + 4y = 8.

Now rewrite both equations, as shown below.

Now when we add the equations together, the x terms

will cancel out and we're left with 5y = 15.

Dividing both sides by 5, <em>y = 3</em>.

To solve for x, plug a 3 in for y in either one of our 2 original equations.

So let's go with our second equation.

Plugging a 3 in for y, we get 2x + (3) = 7.

Now subtract 4 from both sides to get 2x = 4.

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3 years ago

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k0ka [10]

Answer:

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Step-by-step explanation:

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2 years ago

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Find the intersection points of the linear and quadratic functions shown below f(x)=2x-5 g(x)= x2+2x-21

Mice21 [21]

Answer:

$(-4,-13)$ and $(4,3)$ the intersection points.

Step-by-step explanation:

Intersection point of two functions is a common point which satisfies both the functions.

Given functions are,

$f(x)=2x-5$

$g(x)=x^2+2x-21$

For a common point of these functions,

$f(x)=g(x)$

$2x-5=x^2+2x-21$

$-5=x^2-21$

$0=x^2-16$

$x^2=16$

$x=-4,4$

For $x=-4$ ,

$f(-4)=g(-4)=2(-4)-5$

$=-13$

For $x=4$ ,

$f(4)=g(4)=2(4)-5$

$=3$

Therefore, $(-4,-13)$ and $(4,3)$ the intersection points.

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2 years ago

What is the value of x in the figure?<br> NEED HELP ASAP

Daniel [21]

Answer:

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Step-by-step explanation:

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2 years ago

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single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec

givi [52]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

a) Rolling an Odd number in first throw

A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

Total Favorable outcomes (Odd numbers) = 3

Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = $\frac{3}{6} = \frac{1}{2}$

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

Favorable outcomes (Numbers greater than 3 are 4, 5 and 6) = 3

So,

The probability of rolling a number greater than 3 = $\frac{3}{6} = \frac{1}{2}$

These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

So,

Probability of rolling an odd number the first time and a number greater than 3 the second time = $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

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2 years ago