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prisoha [69]
3 years ago
7

$10.4856round to the nearest cent

Mathematics
1 answer:
alexgriva [62]3 years ago
8 0
10.49 (5 or more round up)
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Set up a system of equations needed to solve each probler
goblinko [34]

Answer:

This is not a solvable question, since the least amount of money you can have with this combination is $4.20.

Step-by-step explanation:

Let q = quarters

Let d = dimes

Equation: 0.1d + 0.25q = 3.00

Maximum amount of dimes: 0.1d *42 = 4.2d

8 0
3 years ago
If 1/3 is 0.333 then 3/3 is 0.999 that means 1 doesnt actually equal 1​
sergejj [24]

Answer:

Correct

Step-by-step explanation:

When you type 1/3 into a calculator it should give you something along the lines of .333333334. If you continue to round, eventually you will get 1.

7 0
3 years ago
Read 2 more answers
PLS HELP ILL MARK CROWN
jok3333 [9.3K]

Answer:

4x−7

Step-by-step explanation:

Being given our polynomial:

4x^{2}+ x - 14,

We must find the roots to get our answer.

x = (- 1 ± √(1 - 4*4*(-14)) / 8

x = (- 1 ± √225) / 8

x = ( -1 ± 15) / 8

x₁ = (- 1 + 15)/ 8 = 14/8 = 7 / 4

x₂ = (- 1 - 15) / 8 = - 16/2 = - 8

The factors we came up with:

(x - x₁)(x - x₂)

(x - 7/4)(x + 8)

1/4(4x - 7)(x + 8)

So,

The correct option is C.

:)

6 0
2 years ago
Read 2 more answers
The mark up on an item is $3.75. If the mark up is 35%, what was the original price? Round
oksian1 [2.3K]

Answer:

$10.71

Step-by-step explanation:

\frac{3.75}{y} =\frac{35}{100}

y × 35 = 3.75 × 100

35y = 375

35y ÷ 35 = 375 ÷ 35

y=10\frac{5}{7}

y = 10.7142857143

10.7142857143 round to 10.71

5 0
2 years ago
Which of the following is an equation for the plane through the point (1, 1, −1) and parallel
Bas_tet [7]

The given plane, x-y+z=3, has normal vector \vec n = \langle1,-1,1\rangle. Any plane parallel to this one has the same normal vector.

Let (x,y,z) be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

\langle x,y,z\rangle - \langle 1,1,-1\rangle = \langle x-1, y-1, z+1 \rangle

and this is perpendicular to \vec n.

So the equation of the plane is

\langle x-1, y-1, z+1 \rangle \cdot \vec n = 0 \implies (x-1) - (y-1) + (z+1) = 0 \implies \boxed{x - y + z = -1}

or equivalently,

\boxed{-x + y - z = 1}

6 0
2 years ago
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