All categories

3 years ago

……………………………………………..()1!-!/

Mathematics

1 answer:

alina1380 [7]3 years ago

8 0

Answer:

A. a is where performance is minimal

Step-by-step explanation:

b is representing peak performance.

You might be interested in

140.132 round to the nearst hundreth

lidiya [134]

140.130 is the answer

6 0

3 years ago

Read 2 more answers

Please‼️help me<br>Myanmar Grade7

cricket20 [7]

Answer:

S/175 =18/21

21s=18×175

21s=3150

s=150

69/s =54/36

69×36 =54×s

2484=54s

s=46

5 0

3 years ago

Help please this is due soon! I need you to show the work as well <3 pic below

Dafna1 [17]

Answer:

perimeter: 4x+2 area: x^2+x

Step-by-step explanation:

for perimeter, you add x+x+x+x+1+1, which is 4x+2

for area, you multiply x*x+1, which would be x^2+x

7 0

3 years ago

What is the equation of this line in standard form?

bazaltina [42]

Answer:

Step-by-step explanation: 11x-6y=13

7 0

3 years ago

Read 2 more answers

There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,

lys-0071 [83]

According to given information there are :

5 red balls

4 blue balls

6 yellow balls

10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{total \: red \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{25}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{1}{5}$

<h3>2. what is the probability that the ball chosen is blue ?</h3>

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{total \: blue \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{25}$

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{total \: yellow\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{25}$

<h3>4. what is the probability that the ball chosen is green ?</h3>

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{total \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{25}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{2}{5}$

<h3>5. what is the probability that the ball chosen is not green ?</h3>

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{total \: non \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{15}{25}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{3}{5}$

3 0

2 years ago