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diamong [38]
3 years ago
14

Simplify with positive exponents... Show your work.. -6a^-3 b^9 c / 18a^2 b^-2 C^4

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0

-(b^11)/(3a^5c^3)

go to freemathhelp.com/factoringcalculator.php to help you with things like that

olya-2409 [2.1K]3 years ago
5 0
<span>-6a^-3 b^9 c 
-------------------
18a^2 b^-2 C^4

=  a^-1 b^7
----------------
  -3 c^3

= b^7
-------------
 -3 a^1 c^3</span>
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Ok i have to identify the slope and the y intercept
LuckyWell [14K]

Answer:

m=2

b=-3

Step-by-step explanation:

standard form of the slope equation

y=mx+b

m=2

b=-3

8 0
3 years ago
Read 2 more answers
Someone please help??
Xelga [282]

Answer:

x-axis

Step-by-step explanation:

The asymptote is a straight line that the curve gets closer and closer to but never touches it.

The given exponential function is f(x)=3^x.

The given graph has a horizontal asymptote,

The equation of this horizontal asymptote is y=0.

This is also refers to as the x-axis.

Therefore the asymptote is the x-axis.

6 0
3 years ago
STVU is an isosceles trapezoid. If SV = 6x - 5 and TU = 2x + 7, find the value of x.<br>x=3
Thepotemich [5.8K]
Because <span>STVU is an isosceles trapezoid
so SV = TU
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answer
x = 3</span>
7 0
3 years ago
5. In one year, there were 125 major new automobile types available. If you look at the miles per gallon (MPG) for these vehicle
ziro4ka [17]

Answer:

The answer is "99.82% and 86.99%".

Step-by-step explanation:

In point a:

=P(X < 45)\\\\= P(Z < \frac{45-29.09}{5.46}) \\\\=P(Z < 2.9139)\\\\=0.9982\\\\=99.82\%

In point b:

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5 0
3 years ago
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Sergeeva-Olga [200]

Answer:

2

Step-by-step explanation:

There are two lines of symmetry and here I list them:

1) The first is a horizontal line that divides the square in to even parts such that the top part is the projection of the down one trough the symmetry line (and vice versa).

2) The second one is the vertical line that divides the square in two even sides. Note that this line will also divide both stars at half. The left side will be projected on the right one (and vice versa) trough the symmetry line.

A third line could be thought to be a diagonal between opposite vertices, but notice that the stars projection won't by symmetric in this case.

So, we only have 2 symmetry lines.

4 0
3 years ago
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