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4 years ago

Ax+c=r Solve for x Need help can anybody help?

Mathematics

2 answers:

Sphinxa [80]4 years ago

7 0

Answer:

x = $\frac{r-c}{a}$

Step-by-step explanation:

To find x you need to isolate x.

First you need to isolate the variable term, or the term with x in it, which in this case is ax. To do this you subtract c from each side of the equation. This will give you the equation: ax = r-c.

Next you have completely isolate x. Because x is being multiplied by a, you have to divide each side of the equation by a in order to isolate x. This give you the equation: x = $\frac{r-c}{a}$ which is the solution.

Hope this helps!

kkurt [141]4 years ago

4 0

What are the numbers for the other ones?

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A sequence is defined by the recursive formula f(n + 1) = 1.5f(n). Which sequence could be generated using the formula? –12, –18

Softa [21]

Answer:

The sequence -12 , -18 , -27 , ............ is generated using the formula ⇒ 1st sequence

Step-by-step explanation:

The recursive formula of the sequence is f(n + 1) = 1.5 f(n)

That means there is a constant ratio 1.5 between each two consecutive terms

In sequence -12 , -18 , -27 , ............

The first term is -12

The formula is f(n + 1) = 1.5 f(n)

Use the first term where n = 1 to find the 2nd term

∵ f(1) = -12

- Substitute n by 1 in the given formula

∵ f(1 + 1) = 1.5 f(1)

∴ f(2) = 1.5(-12)

∴ f(2) = -18

Use the second term where n = 2 to find the 3rd term

∵ f(2) = -18

- Substitute n by 2 in the given formula

∵ f(2 + 1) = 1.5 f(2)

∴ f(3) = 1.5(-18)

∴ f(3) = -27

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3 years ago

Find the equation of a line that passes through (-5,4) and us parallel to y=-6/7x+3

irina [24]

Given:

The given equation of line is

$y=-\dfrac{6}{7}x+3$

To find:

The equation of line that passes through (-5,4) and is parallel to the given line.

Solution:

Slope intercept form of a line is

$y=mx+b$ ...(i)

where, m is slope and b is y-intercept.

We have,

$y=-\dfrac{6}{7}x+3$ ...(ii)

On comparing (i) and (ii), we get

$m=-\dfrac{6}{7}$

Slope of given line is $m=-\dfrac{6}{7}$ .

Slope of parallel lines are same. So, slope of parallel line is $m=-\dfrac{6}{7}$ .

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$y-y_1=m(x-x_1)$

$y-4=-\dfrac{6}{7}(x-(-5))$

$y-4=-\dfrac{6}{7}(x+5)$

$y-4=-\dfrac{6}{7}x-\dfrac{30}{7}$

Adding 4 on both sides, we get

$y=-\dfrac{6}{7}x-\dfrac{30}{7}+4$

$y=-\dfrac{6}{7}x+\dfrac{-30+28}{7}$

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