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3 years ago

Ax+c=r Solve for x Need help can anybody help?

Mathematics

2 answers:

Sphinxa [80]3 years ago

7 0

Answer:

x = $\frac{r-c}{a}$

Step-by-step explanation:

To find x you need to isolate x.

First you need to isolate the variable term, or the term with x in it, which in this case is ax. To do this you subtract c from each side of the equation. This will give you the equation: ax = r-c.

Next you have completely isolate x. Because x is being multiplied by a, you have to divide each side of the equation by a in order to isolate x. This give you the equation: x = $\frac{r-c}{a}$ which is the solution.

Hope this helps!

kkurt [141]3 years ago

4 0

What are the numbers for the other ones?

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faust18 [17]

Answer:

Step-by-step explanation:

Let the numbers of steps you can take to reach your goal be x

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3 years ago

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3 years ago

A linear model is given for the data in the table: y=1.25x+2.

Fed [463]

Answer:

Option A

Step-by-step explanation:

Given that A linear model is given for the data in the table: y=1.25x+2.

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x 2 3 4 8 10 16 20 24 Total

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y(P) 4.5 5.75 7 12 14.5 22 27 32

DEv 1.5 1.75 0 0 1.5 0 1 2 7 75

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Dev represents the absolute difference

Hence answer is option

A.7.75

8 0

3 years ago

Need help with finding the surface area and volume for this please thanks I just need step by step help so I can understand it m

Allisa [31]

Answer:

144

Step-by-step explanation:

First, do the top and bottom. The top is 2*4*3 or 24, and the bottom is 6*4 or 24.

Now, do the sides. It is a staircase that you can split into 6 2x2 blocks, or 6*4=24. Do the same with the other side to get 24 again.

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3 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

3 years ago