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lbvjy [14]
4 years ago
11

Ax+c=r Solve for x Need help can anybody help?

Mathematics
2 answers:
Sphinxa [80]4 years ago
7 0

Answer:

x = \frac{r-c}{a}

Step-by-step explanation:

To find x you need to isolate x.

First you need to isolate the variable term, or the term with x in it, which in this case is ax. To do this you subtract c from each side of the equation. This will give you the equation: ax = r-c.

Next you have completely isolate x. Because x is being multiplied by a, you have to divide each side of the equation by a in order to isolate x. This give you the equation: x = \frac{r-c}{a} which is the solution.

Hope this helps!

kkurt [141]4 years ago
4 0
What are the numbers for the other ones?
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SOLUTIONS

Solve a given equations or algebraic symbols?

\begin{gathered} f(x)=x^2+2x \\ g(x)=1-x^2 \end{gathered}

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\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}

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\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}

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\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}

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\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}

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