→ Substitute cos 2x and sin 2x by their expressions
→ Subtract both sides by sin x
→ Take sin x as a common factor in the right side
From the graph, the equation has 4 solutions, the intersection points between the 2 graphs
Mr. James has 53 paint brushes to share with 4 classes. Are there enough for each class to have the same amount? Are there any l
eft over? Explain how you know
1 answer:
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Answer:
min = a_1
for i:= 2 to n:
if < min then min =
return min
Step-by-step explanation:
We call the algorithm "minimum" and a list of natural numbers
So lets first set the minimum to
min = a_1
now we want to check all the other numbers.
We can use a simple for loop, to find the minimum
min = a_1
for i:= 2 to n:
if < min then min =
return min