Franklin picked 342 potatoes out of his garden this season and will store them in 6 baskets.

A cosmetic company makes three bottles of scented lotion using the recipe shown. Each bottle holds a different amount of lotion.

seropon [69]

Answer:

Part 1) Bottle 1 (vanilla=1,almond=3,pineapple=4)

Part 2) Bottle 2 (vanilla=2,almond=6,pineapple=8)

Part 3) Bottle 3 (vanilla=1 1/2,almond=4 1/2,pineapple=6)

Step-by-step explanation:

Let

x ----> the amount of vanilla sent

y ----> amount of almond sent

z ----> the amount of pineapple sent

we know that

$x:y:z=\frac{1}{8}:\frac{3}{8}:\frac{1}{2}$

so

$\frac{x}{y}=\frac{1}{8}:\frac{3}{8}$

$\frac{x}{y}=\frac{1}{3}$

$x=\frac{y}{3}$ -----> equation A

$\frac{x}{z}=\frac{1}{8}:\frac{1}{2}$

$\frac{x}{z}=\frac{1}{4}$

$x=\frac{1}{4}z$ -----> equation B

$\frac{y}{z}=\frac{3}{8}:\frac{1}{2}$

$\frac{y}{z}=\frac{3}{4}$

$y=\frac{3}{4}z$ -----> equation C

Part 1) Bottle 1

vanilla=?

almond=?

pineapple=4

we have

$z=4$

Find the value of x

substitute the value of z in equation B

$x=\frac{1}{4}(4)$

$x=1$

Find the value of y

substitute the value of z in equation C

$y=\frac{3}{4}(4)$

$y=3$

therefore

Bottle 1

vanilla=1

almond=3

pineapple=4

Part 2) Bottle 2

vanilla=?

almond=6

pineapple=?

we have

$y=6$

Find the value of x

substitute the value of y in equation A

$x=\frac{6}{3}=2$

Find the value of z

substitute the value of x in equation B

$2=\frac{1}{4}z$

solve for z

$z=8$

therefore

Bottle 2

vanilla=2

almond=6

pineapple=8

Part 3) Bottle 3

vanilla=1 1/2

almond=?

pineapple=?

we have

$x=1\frac{1}{2}$

convert to an improper fraction

$x=1\frac{1}{2}=\frac{1*2+1}{2}=\frac{3}{2}$

Find the value of y

substitute the value of x in equation A

$\frac{3}{2}=\frac{y}{3}$

$y=\frac{9}{2}$

convert to mixed number

$y=\frac{9}{2}=\frac{8}{2}+\frac{1}{2}=4\frac{1}{2}$

Find the value of z

substitute the value of x in equation B

$\frac{3}{2}=\frac{1}{4}z$

$z=6$

therefore

Bottle 3

vanilla=1 1/2

almond=4 1/2

pineapple=6

5 0

3 years ago

Read 2 more answers

5

stellarik [79]

Answer:

(0,2),(1,6),(−2,−6) are solutions

8 0

3 years ago

•What is the domain for the graph below?

solmaris [256]

C All real numbers except 5 and 0

6 0

3 years ago

Read 2 more answers

Jim is 3 times as old as his cousin Anthony the difference in their age is 18.How old is Jim?

IgorC [24]

Let's create expressions and equations to model this situation. Let Anthony's age be a.

"Jim is 3 times as old as his cousin, Anthony." Jim's age is 3a.
"The difference in their age is 18." 3a - a = 18

How old is Jim?

Let's solve the above equation for a to first find Anthony's age.

3a - a = 18
2a = 18
a = 9

Remember, Jim's age is represented by the expression 3a. Substitute Anthony's age, 9, into the expression to find Jim's age.

3a
3(9)
27

Answer:
Jim is 27 years old.

6 0

3 years ago

Maurice made a model of the steel tabletop his model measures 7 inches by 13 inches is the model simular to the original

Levart [38]

The first example has students building upon the previous lesson by applying the scale factor to find missing dimensions. This leads into a discussion of whether this method is the most efficient and whether they could find another approach that would be simpler, as demonstrated in Example 2. Guide students to record responses and additional work in their student materials.
§ How can we use the scale factor to write an equation relating the scale drawing lengths to the actual lengths?
!
ú Thescalefactoristheconstantofproportionality,ortheintheequation=or=!oreven=
MP.2 ! whereistheactuallength,isthescaledrawinglength,andisthevalueoftheratioofthe drawing length to the corresponding actual length.
§ How can we use the scale factor to determine the actual measurements?
ú Divideeachdrawinglength,,bythescalefactor,,tofindtheactualmeasurement,x.Thisis
! illustrated by the equation = !.
§ How can we reconsider finding an actual length without dividing?
ú We can let the scale drawing be the first image and the actual picture be the second image. We can calculate the scale factor that relates the given scale drawing length, , to the actual length,. If the actual picture is an enlargement from the scale drawing, then the scale factor is greater than one or
> 1. If the actual picture is a reduction from the scale drawing, then the scale factor is less than one or < 1.
Scaffolding:
A reduction has a scale factor less than 1, and an enlargement has a scale factor greater than 1.
Lesson 18: Computing Actual Lengths from a Scale Drawing.

8 0

3 years ago