The emf is induced in the wire will be 1.56 ×10 ⁻³ V. The induced emf is the product of the magnetic field,velocity and length of the wire.
<h3>What is induced emf?</h3>
Emf is the production of a potential difference in a coil as a result of changes in the magnetic flux passing through it.
When the flux coupling with a conductor or coil changes, electromotive Force, or EMF, is said to be induced.
The given data in the problem is;
B is the magnitude of the magnetic field,= 5.0 ×10⁻⁵ T
V(velocity)=125 M/SEC
L(length)=25 cm=0.25 m
The maximum emf is found as;
E=VBLsin90°
E=125 × 5.0 × 10⁻⁵ ×0.25
E=1.56 ×10 ⁻³ V
Hence, the emf is induced in the wire will be 1.56 ×10 ⁻³ V
To learn more about the induced emf, refer to the link;
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Answer:
I think it is "A" because the wind systems are created by uneven heating of Earth's surface.It also may help form large global wind patterns.
Explanation:
Density of copper: 8,9
Density of steel: 7,7
Density of aluminum: 2,7
And
Resistivity of copper: 1,7
Resistivity of steel: 16,9
Resistivity of aluminum: <span>2,7</span>
Hope I Helped You!!! :-)
Have A Good Day!!!
Answer:
The light transmitted through the system will be 0.125*I₀.
Explanation:
The light transmitted through the system can be found using Malus Law:
(1)
Where:
I: is the intensity of the light transmitted
I₀: is the initial intensity
θ is the angle relative to the first polarizer’s = 60°
Because the light transmitted by the first polarizer is dropped by half, the equation (1) results as:
Therefore, the light transmitted through the system will be 0.125*I₀.
I hope it helps you!
