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Inessa [10]
4 years ago
13

How are electromagnetic waves that are produced by oscillating charges and sound waves that are produced by oscillating tuning f

orks similar?
Physics
1 answer:
Dovator [93]4 years ago
8 0
They are both created by waves of different forms of energy... sound is the oscillation of other substances, called a medium, while the electromagnetic waves are oscillating through electromagnetic energy. 
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a car travels West 50km for 2 hours before heading south at a rate of 30 km per hour for 1.5 hours. What is the car's average sp
inn [45]

Answer:

Explanation:

average speed is distance traveled over time

v = (50 + 30(1.5)) / (2 + 1.5) = 27.1428571...

v = 27 km/hr

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3 years ago
Guys I just need this question, cmon help me
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There can be an experiment run using two or more cleansers at the same time as the manufacturers' one
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Which of the following is an example of an acceptable time to ignore the rules and etiquette of a sport?
Helga [31]

Answer:

D-it's never acceptable to ignore rules and etiquette

Explanation:

4 0
2 years ago
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Violet light (λ = 400 nm) passing through a diffraction grating for which the slit spacing is 6.0 μm forms a pattern on a screen
sergey [27]

Answer:

3 order dark fringe

Explanation:

y = Distance from central bright fringe = 204 mm

λ = Wavelength = 400 nm

L = Distance between screen and source = 1 m

d = Slit distance = 6 μm

tan\theta =\frac{y}{L}\\\Rightarrow tan\theta =\frac{204}{1000}=0.2012^{\circ}

dsin\theta=m\lambda\\\Rightarrow m=\frac{dsin\theta}{\lambda}\\\Rightarrow m=\frac{6\times 10^{-6}sin0.2012}{400\times 10^{-9}}=2.9982\approx 3

Order of fringe is 3

So, it is a Dark order fringe

3 0
3 years ago
Two protons in an atomic nucleus are typically separated by a distance of 2 ✕ 10-15 m. The electric repulsion force between the
castortr0y [4]

Answer:

The magnitude of the electric force between the to protons will be 57.536 N.

Explanation:

We can use Coulomb's law to find out the force, in scalar form, will be:

F \ = \ \frac{1}{4 \pi \epsilon_0 } \frac{q_1 q_2}{d^2}.

Now, making the substitutions

d \ = \ 2.00 * 10 ^{-15} \ m,

q_1 = q_2 = 1.60 * 10 ^ {-19} \ C,

\frac{1}{4\pi\epsilon_0}=8.99 * 10^9 \frac{Nm^2}{C^2},

we can find:

F \ = \ 8.99 * 10^9 \frac{Nm^2}{C^2} \frac{(1.60 * 10 ^ {-19} \ C)^2}{(2.00 * 10 ^{-15} \ m)^2}.

F \ = 57.536 N.

Not so big for everyday life, but enormous for subatomic particles.

4 0
3 years ago
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