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Inessa [10]
4 years ago
13

How are electromagnetic waves that are produced by oscillating charges and sound waves that are produced by oscillating tuning f

orks similar?
Physics
1 answer:
Dovator [93]4 years ago
8 0
They are both created by waves of different forms of energy... sound is the oscillation of other substances, called a medium, while the electromagnetic waves are oscillating through electromagnetic energy. 
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The sun is directly overhead at the equator on what day of the year
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Both equinoxes ... September 21 and March 21.
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Lori rented a car for one day. The daily rental rate was $12.50 cent per mile. The total cost of her rental was $46. How many mi
larisa86 [58]
C. Cause nddndjdndjdj
3 0
3 years ago
n the Bohr model of the hydrogen atom (see Section 39.3), in the lowest energy state the electron orbits the proton at a speed o
Ivahew [28]

Answer:

(a) T=1.5*10^{-6}s

(b) I=1.1*10^{-3}A

(c) \mu=9.71*10^{-24}A\cdot m^2

Explanation:

(a) The orbital period is the time that the electron spend to travel the orbit of the atom. Thus, it is given by the length of the circular orbit divided by its velocity:

T=\frac{2\pi r}{v}\\T=\frac{2\pi(5.3*10^{-11}m)}{2.2*10^{6}\frac{m}{s}}\\T=1.5*10^{-6}s

(b) Current means charge over time, So, in this case is charge over period:

I=\frac{q}{t}\\I=\frac{e}{T}\\I=\frac{1.6*10^{-19}C}{1.5*10^{-6}s}\\\\I=1.1*10^{-3}A

(c) Magnetic moment is given by:

\mu=IA

Here A is the area of the orbit.

\mu=I\pi r^2\\\mu=(1.1*10^{-3}A)\pi(5.3*10^{-11}m)^2\\\mu=9.71*10^{-24}A\cdot m^2

4 0
3 years ago
if i roll pieces of allium foil in a ball what property of aluminium foil changes as a result of my action​
MArishka [77]

Answer:

Malleability

Explanation:

The ability to roll aluminum foil in a ball is the property of metal called malleability.

  • Metallic bonds in metals makes it possible for them to take different shape without losing internal cohesion.
  • Metals are malleable and they posses a wide range of physical properties.
  • A malleable metal can be beaten into sheets and molded into many shapes.
6 0
3 years ago
An 20-cm-long bicycle crank arm, with a pedal at one end, is attached to a 25-cm-diameter sprocket, the toothed disk around whic
Andrej [43]

Answer:

0.033815 m/s²

12.48810875 m

Explanation:

t = Time taken = 12 s

\omega_f = Final angular velocity = 95 rpm

\omega_i = Initial angular velocity = 64 rpm

\alpha = Angular acceleration

\theta = Angle of rotation

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{95\times \frac{2\pi}{60}-64\times \frac{2\pi}{60}}{12}\\\Rightarrow \alpha=0.27052\ rad/s^2

Tangential acceleration is given by

a_t=\alpha r\\\Rightarrow a_t=0.27052\times 0.125\\\Rightarrow a_t=0.033815\ m/s^2

The tangential acceleration of the pedal is 0.033815 m/s²

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{\left(95\times\frac{2\pi }{60}\right)^2-\left(64\times\frac{2\pi}{60}\right)^2}{2\times 0.27052}\\\Rightarrow \theta=99.90487\ rad

Linear displacement would be 99.90487\times \frac{1}{2\pi}\times 2\pi\times 0.125=12.48810875\ m

Length of chain that passes in the interval is 12.48810875 m

4 0
3 years ago
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