Melting freezing and boiling are molecular changes
The volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
<h3>What is volume?</h3>
Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.
<h3>
Volume of the tire</h3>
The volume of the tire is the measure of the product of area and thickness of the tire.
The volume of the tire is calculated as follows;
Radius of the tire = 0.5 x 26" = 13"
Volume of the tire = Area x thickness
Volume of the tire = πr² x h
where;
- r is the radius of the tire
- h is the thickness of the tube
Volume of the tire = π(13)² x (2.125)
Volume of the tire = 1,128.2 cubic inch
Thus, the volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
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Answer:
G M m / R^2 = F force of attraction for proton
K e^2 / r^2 = F force of attraction between 2 protons
G M m / R^2 = K e^2 / r^2
r^2 = K e^2 R^2 / (G M m)
r^2 = 9E9 * (1.6E-19)^2 * (6.37E6)^2 / (6.67E-11 * 5.98E24 * 1.7E-27)
r^2 = 9 * 2.56 * 40.6 / (6.67 * 5.98 * 1.7) * 10^-19
r^2 = 1.38 * 10^-30
r = 1.17E-15 m
Answer:
v = c / n (n = 1 for air)
v = c / 1.33 = 3 * 10E8 m/s / 1.33 = 2.25 * 10E8 m/s
Answer:
4.14 cm.
Explanation:
Given,
For Coil 1
radius of coil, r₁ = 5.6 cm
Magnetic field, B₁ = 0.24 T
For Coil 2
radius of coil, r₂ = ?
Magnetic field, B₂ = 0.44 T
Using formula of maximum torque
Since both the coil experience same maximum torques
now,
Radius of the coil 2 is equal to 4.14 cm.
