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Thepotemich [5.8K]

3 years ago

5

Lori rented a car for one day. The daily rental rate was $12.50 cent per mile. The total cost of her rental was $46. How many mi

les did she drive that day? A.134 B.50 C.96 D.46

1 answer:

larisa86 [58]3 years ago

3 0

C. Cause nddndjdndjdj

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An invalid argument with one true premise, one false premise, and a true conclusion.

murzikaleks [220]

So if a valid argument does have a false conclusion, it cannot have all true premises. Thus at least one premise must be false. ... If an invalid argument has all true premises, then the conclusion must be false. FALSE: It is possible for an invalid argument to have all true premises and a true conclusion.

4 0

3 years ago

You kick a soccer ball with a speed of 31 m/s at an angle of 50 degrees. How long does it take the ball to reach the top of its

Harlamova29_29 [7]

Answer:

Reaches max height at t = 2.42s.

Explanation:

I've assumed we are neglecting air resistance. If not let me know and I'll update.

We want to examine the behaviour of the ball in the y-direction. In the absence of air resistance the only force acting on the ball is gravity, which produces an acceleration in the negative y direction.

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3 years ago

What type of objects exert gravitational pull? (5 points) Only living objects Only space objects All objects having mass All sub

Yanka [14]

Answer:

Every object in the universe that has mass exerts a gravitational pull, or force, on every other mass. The size of the pull depends on the masses of the objects. You exert a gravitational force on the people around you, but that force isn't very strong, since people aren't very massive.

6 0

3 years ago

Consider a string of total length L, made up of three segments of equal length. The mass per unit length of the first segment is

zzz [600]

Answer:

Explanation:

Length of each segment is $\frac{L}{3}$

Speed of wave in first segment is $v_1=\sqrt{\frac{T_s}{\mu}}$

Speed of wave in second segment is $v_2=\sqrt{\frac{T_s}{2\mu}}$

Speed of wave in third segment is $v_3=\sqrt{\frac{T_s}{\frac{\mu}{4}}}=\sqrt{\frac{4T_s}{\mu}}$

Now time for the transverse wave to propagate is

$t=t_1 + t_2 + t_3\\=\frac{(\frac{L}{3})}{v_1}+\frac{(\frac{L}{3})}{v_2} + \frac{(\frac{L}{3})}{v_3}\\\\=(\frac{L}{3})(\frac{1}{\sqrt{\frac{T_s}{\mu}}} + \frac{1}{\sqrt{\frac{T_s}{2\mu}}} + \frac{1}{\sqrt{\frac{4T_s}{\mu}}})$

simplifying we get

$t=(\frac{3+2\sqrt{2}}{6})L\sqrt{\frac{\mu}{T_s}}$

3 0

3 years ago

A compound microscope is made with an objective lens (f0 = 0.900 cm) and an eyepiece (fe = 1.10 cm). The lenses are separated by

Marizza181 [45]

Answer:

-252.52

Explanation:

L = Distance between lenses = 10 cm

D = Near point = 25 cm

$f_o$ = Focal length of objective = 0.9 cm

$f_e$ = Focal length of eyepiece = 1.1 cm

Magnification of a compound microscope is given by

$m=-\frac{L}{f_o}\frac{D}{f_e}\\\Rightarrow m=-\frac{10}{0.9}\times \frac{25}{1.1}\\\Rightarrow m=-252.52$

The angular magnification of the compound microscope is -252.52

6 0

3 years ago