Answer:
The second one
Explanation:
The second one is joining so it is the one which belongs to X, first one belongs to Z
Answer:
Pressure = ρgh
pressure (p) is measured in pascals (Pa)
density (ρ) is measured in kilograms per metre cubed (kg/m3)
The fore of gravitational field strength (g) is measured in N/kg or m/s 2
height of column (h) is measured in metres (m)
Answer = 235,200 Pa
Explanation:
Pressure = ρgh
Pressure = 1,000 x 9.8 x 24
Pressure = 235,200 Pa
When two different air masses meet, a boundary is formed. the boundary between two air masses is called a front. weather at a front is usually cloudy and stormy. there at four different fronts: cold, warm, stationary, and occluded
Answer:
Part a)
![dF = -\frac{mv^2}{r^2} dr](https://tex.z-dn.net/?f=dF%20%3D%20-%5Cfrac%7Bmv%5E2%7D%7Br%5E2%7D%20dr)
Part b)
![dF = \frac{2mvdv}{r}](https://tex.z-dn.net/?f=dF%20%3D%20%5Cfrac%7B2mvdv%7D%7Br%7D)
Part c)
![dT = - \frac{2\pi r}{v^2} dv](https://tex.z-dn.net/?f=dT%20%3D%20-%20%5Cfrac%7B2%5Cpi%20r%7D%7Bv%5E2%7D%20dv)
Explanation:
Part a)
As we know that force on the passenger while moving in circle is given as
![F = \frac{mv^2}{r}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D)
now variation in force is given as
![dF = -\frac{mv^2}{r^2} dr](https://tex.z-dn.net/?f=dF%20%3D%20-%5Cfrac%7Bmv%5E2%7D%7Br%5E2%7D%20dr)
here speed is constant
Part b)
Now if the variation in force is required such that r is constant then we will have
![F = \frac{mv^2}{r}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D)
so we have
![dF = \frac{2mvdv}{r}](https://tex.z-dn.net/?f=dF%20%3D%20%5Cfrac%7B2mvdv%7D%7Br%7D)
Part c)
As we know that time period of the circular motion is given as
![T = \frac{2\pi r}{v}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%20r%7D%7Bv%7D)
so here if radius is constant then variation in time period is given as
![dT = - \frac{2\pi r}{v^2} dv](https://tex.z-dn.net/?f=dT%20%3D%20-%20%5Cfrac%7B2%5Cpi%20r%7D%7Bv%5E2%7D%20dv)
Answer:
D
Explanation:
<em>The correct answer would be in the axle of the wheels while you ride your bicycle.</em>
Options A, B, and C requires that the forces of friction is increased in order to have more control.
However, option D requires that there is a minimal frictional force in the axle of the wheels of a bicycle while riding so that a little effort would be required to keep the bicycle moving.
<u>The lesser the friction, the lower the effort that would be needed to keep the bicycle moving and vice versa.</u>