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elena-s [515]
1 year ago
12

A 0. 50 l sample of a gas has a mass of 11. 3 g at stp. what is the mass of 1. 00 mol of this gas? in other words, what is the m

olar mass (molecular weight)?
Physics
1 answer:
Ilia_Sergeevich [38]1 year ago
6 0

the molar mass of the given sample is 44.24kg.

To find the answer, we have to know about the concept of mole.

<h3>How to find the molar mass of the sample?</h3>
  • Mole is the amount of substance that containing Avogadro number of particles.
  • We can write the expression for mole as,

                      mole,n=\frac{m}{M}

where, m is the given mass and M is the molar mass.

  • Given that, the 0.5 mol of sample has a mass of 11.3g. Thus the molar mass will be,

                      n=\frac{m}{M} \\M=\frac{n}{m}=\frac{0.5}{11.3*10^{-3}}  =44.24kg

  • The mass of 1 mole of given sample will be,

                       m=n*M=1*44.24kg=44.24kg

Thus, we can conclude that, the molar mass of the given sample is 44.24kg.

Learn more about the mole here:

brainly.com/question/1427235

#SPJ4

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USPshnik [31]

Odpowiedź:

0,049 m / s

Wyjaśnienie:

Biorąc pod uwagę, że:

Dystans biegu = 900m

Czas trwania = 205 minut

Długość przejścia = 300 m

Zajęty czas = 205 minut

Średnia prędkość :

(Przebieg + pokonany dystans) / całkowity czas

Średnia prędkość :

(900 m +. 300 m) / 205 + 205

1200 m / 410 minut

Minuty do sekund

1200 / (410 * 60)

1200/24600

= 0,0487804

= 0,049 m / s

8 0
2 years ago
Please answer any of these thanks !
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Speed = (256 Hz) x (1.3 m) = 332.8 meters per second

 2).  If the instrument is played louder, the amplitude of the waves increases.
On the oscilloscope, they would appear larger from top to bottom, but the
horizontal size of each wave doesn't change.

If the instrument is played at a higher pitch, then the waves become shorter,
because 'pitch' is directly related to the frequency of the waves, and higher
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If the instrument plays louder and at higher pitch, the waves on the scope
become taller and there are more of them across the screen.

3).  The equation is:  Frequency = (speed) / (wavelength)
(Notice that this is exactly the same as the equation up above in question #1,
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Frequency = 300,000,000 meters per second / 1,500 meters = 200,000 per second.

That's ' 200 k Hz ' .

Note:
I didn't think anybody broadcasts at 200 kHz, so I looked up BBC Radio 4
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Answer:

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Read 2 more answers
A planet has a surface temperature of 95.0 K and an atmospheric pressure of 1.60 atm. If 4.87 L of atmosphere has a mass of 28.6
mr Goodwill [35]

Answer:

M=28.88 gm/mol

Explanation:

Given that

T= 95 K

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V= 4.87 L

m = 28.6 g

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We know that gas equation for ideal gas

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Now by putting the values

P V = n R T

1.6 x 4.87  = n x 0.08206 x 95

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M=Molar mass

n=\dfrac{m}{M}

0.99=\dfrac{28.6}{M}

M=28.88 gm/mol

3 0
2 years ago
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