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elena-s [515]
2 years ago
12

A 0. 50 l sample of a gas has a mass of 11. 3 g at stp. what is the mass of 1. 00 mol of this gas? in other words, what is the m

olar mass (molecular weight)?
Physics
1 answer:
Ilia_Sergeevich [38]2 years ago
6 0

the molar mass of the given sample is 44.24kg.

To find the answer, we have to know about the concept of mole.

<h3>How to find the molar mass of the sample?</h3>
  • Mole is the amount of substance that containing Avogadro number of particles.
  • We can write the expression for mole as,

                      mole,n=\frac{m}{M}

where, m is the given mass and M is the molar mass.

  • Given that, the 0.5 mol of sample has a mass of 11.3g. Thus the molar mass will be,

                      n=\frac{m}{M} \\M=\frac{n}{m}=\frac{0.5}{11.3*10^{-3}}  =44.24kg

  • The mass of 1 mole of given sample will be,

                       m=n*M=1*44.24kg=44.24kg

Thus, we can conclude that, the molar mass of the given sample is 44.24kg.

Learn more about the mole here:

brainly.com/question/1427235

#SPJ4

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3 In a television tube, an electron starting from rest experiences a force of 4.0 × 10−15 N over a distance of 50 cm. The final
MAXImum [283]

Answer:

The final speed of the electron = 2.095×10⁸ m/s

Explanation:

From newton's fundamental equation of dynamics,

F = ma ........................Equation 1

Where F = force, m = mass of the electron, a = acceleration of the electron.

making a the subject of the equation,

a = F/m.................... Equation 2

Given: F = 4.0×10⁻¹⁵ N,

Constant: m =  9.109×10⁻³¹ kg.

Substituting into equation 2

a = 4.0×10⁻¹⁵/9.109×10⁻³¹

a = 4.39×10¹⁶ m/s².

Using newton's equation of motion,

v² = u²+2as .......................... Equation 3

Where v = final velocity of the electron, u = initial velocity of the electron, a = acceleration of the electron, s = distance covered by the electron.

Given: u = 0 m/s(at rest), s = 50 cm = 0.5 m, a = 4.39×10¹⁶ m/s²

Substituting into equation 3

v² = 0² + 2(0.5)(4.39×10¹⁶)

v = √(4.39×10¹⁶)

v = 2.095×10⁸ m/s

Thus the final speed of the electron = 2.095×10⁸ m/s

7 0
3 years ago
What’s something that is 50cm
Firlakuza [10]

Answer:

50 cm is equivalent to 19,6850393701 inches.

Explanation:

A meter has 100 centimeters. 100 millimeters make one centimeter. The centimeter can be written as cm. While calculating the surface area of an object, the unit of measurement becomes cm2.

5 0
3 years ago
Read 2 more answers
A cubic metal box with sides of 17 cm contains air at a pressure of 1 atm and a temperature of 278 K. The box is sealed so that
const2013 [10]

Answer:

F = 3.98 kN

Explanation:

GIVEN DATA:

sides of box = 17 cm

pressure = 1 atm = 101325 N/m2

T2 = 378K

T1 = 278 K

final pressure can be calculate by using below relation

\frac{P_{1}}{P_{2}}=\frac{T_{1}}{T_{2}}

we know that

force = pressure * area

therefore force is

F =(\frac{T_{1}}{T_{2}}*P_{1})A

F =(\frac{378}{278}*101325)(17*10^{-2})^{2}

F = 3.98 kN

5 0
3 years ago
Which of these is not an example of
prohojiy [21]

Answer:

A) The process that give us day  and night.

Explanation:

From the answer choices provided the one that is not an example of this is the process that give us day  and night. This is because, the day/night cycle occurs as the Earth spins on it's axis. This cause one side of the Earth to be facing the Sun, which is the side that is currently experiencing day time while the other side is experiencing night time. As the Earth spins the cycles repeat. This is not an example of revolving.

5 0
3 years ago
A laser source has a bandwidth of 30GHz (a) Calculate the coherence length of the source b) What is the time separation of secti
abruzzese [7]

Explanation:

It is given that,

Bandwidth of a laser source, f=30\ GHz=30\times 10^9\ Hz

(b) Let t is the time separation of sections of sections of the light wave that can still interfere. The time period is given by :

T=\dfrac{1}{f}

T=\dfrac{1}{30\times 10^9}

T=3.33\times 10^{-11}\ s

(a) Let h is the coherence length of the source. It is given by :

l=c\times T

c is the speed of light

l=3\times 10^8\times 3.33\times 10^{-11}

l = 0.0099 m

Hence, this is the required solution.

6 0
3 years ago
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