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Xelga [282]
4 years ago
6

Is platinum carbonate naturally occurring or human made?

Physics
1 answer:
skad [1K]4 years ago
6 0

Answer:

no

Explanation:

Platinum is a noble metal. The concentrations of platinum in the soil, water and air are very minimal. ... Finally, a danger of platinum is that it can cause potentiation of the toxicity of other dangerous chemicals in the human body, such as selenium.

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What do we call the certain electrons that are able to sometimes wander<br> away or be shared? *
Natalka [10]

Answer:

compond

Explanation:

5 0
3 years ago
Carbon burns with oxygen to produce carbon dioxide gas. which of these shows the correct chemical reaction?
Ksju [112]
B

Chemical equations always have an arrow
4 0
4 years ago
Read 2 more answers
If the direction of the position is north and the direction of the velocity is up, then what is the direction of the angular mom
Kay [80]

Answer:

the direction of angular momentum = EAST

Explanation:

given

Direction of position = r = north

Direction of velocity = v = up

angular momentum = L = m(r x v)

where m is the mass, r is the radius, v is the velocity

utilizing the right hand rule, the right finger heading towards the course of position vector and curl them toward direction of velocity, at that point stretch thumb will show the bearing of the angular momentum.

then L = north x up = East

6 0
3 years ago
A parallel-plate capacitor in air has a plate separation of 1.25 cm and a plate area of 25.0 cm2. The plates are charged to a po
Archy [21]

Answer:

(a) Since net charge remains same,after immersion Q is same

(b) I. 14.56pF ii. 3.05V

(c) ΔU = 5.204nJ

Explanation:

a)

C = kεA/d

k=1 for air

ε is 8.85x10-12F/m

A = .0025m2

d = .125m

C = 8.85x10-12x.0025/.125 = 1.77x10-13F = 0.177pF

Q = CV = .177pF * 244V = 43.188pC

Since net charge remains same,after immersion Q is same

b)

C = kεA/d, for distilled water k is approx. 80

Cwater = Cair x k

=0.177pF x 80 = 14.16pF

Q is same and C is changed V=Q/c holds. where Q is still 43.188pC and C is now 14.16pF, so V = 43.188pC/14.16pF = 3.05V

c) Change in energy: ΔU = Uwater - Uair

Uwater = Q2/2C = (43.188)2/2x.177pF = 5.27nJ

Uair = Q2/2C = (43.188)2/2x14.16pF = 0.066nJ

ΔU = 5.204nJ

6 0
3 years ago
A toy cannon tosses a rubber ball straight upward. A motion sensor measures the speed of the ball as it leaves the cannon. Using
mezya [45]

Answer:

With this information is not possible to calculate the mass.

Explanation:

This is a characteristic problem of energy conservation, where kinetic energy becomes potential energy. For this particular problem, we have the initial speed as input data. The moment the ball comes out of the cannon we have the maximum kinetic energy, as the ball goes up the ball will gain more potential energy as the ball loses kinetic energy, until the moment the ball reaches the maximum height. At the maximum height point, the ball will have its maximum potential energy while its kinetic energy is zero. In other words, all the kinetic energy that was, in the beginning, was transformed into potential energy.

E_{p}=E_{k}\\m*g*h=0.5*m*v^2

In the above equation the masses are canceled and we can determine the maximum height, by means of the initial speed.

h=\frac{0.5*v^2}{g} [m]

But the mass cannot be determined, since it would be necessary to know the value of the energy, in order to determine the value of the mass.

3 0
3 years ago
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