First off, let's keep in mind that perpendicular lines have negative reciprocal slopes, hmmm so what's the slope of y = 2x + 5?
well, notice, that equation is in slope-intercept form, thus
.
so, we're really looking for the equation of a line whose slope is -1/2 and runs through 1,4.
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
Because it has more mass so with less mass it accelerates faster. That is newtons 2nd law of motion.
Using SOH CAH TOA, you have the Opposite side and you need to work out the Hypotenuse so you will use SOH. This means that the opposite divided by the sine of the angle is the hypotenuse: 18/sin(35) = x = 31.4
Rime factorization of 2001:
By prime factorization of 2001 we follow 5 simple steps:
1. We write number 2001 above a 2-column table
2. We divide 2001 by the smallest possible prime factor
3. We write down on the left side of the table the prime factor and next number to factorize on the ride side
4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)
5. We continue until we reach 1 on the ride side of the table
<span>2001<span>prime factorsnumber to factorize</span><span>3667</span><span>2329</span><span>291</span></span>
<span>Prime factorization of 2001 = 1×3×23×29= </span><span>1 × 3 × 23 × 29</span>
