Find a consecutive odd numbers where the sum of the first three numbers is 15 greater then the final two numbers.

Mathematics

1 answer:

xenn [34]3 years ago

4 0

Answer:

15, 17, 19

Step-by-step explanation:

x + x+2 + x+4 = 15 + (x+2 + x+4)

3x + 6 = 15 + 2x + 21

x = 15

x+2 = 17

x+4 = 19

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