Find a consecutive odd numbers where the sum of the first three numbers is 15 greater then the final two numbers.
1 answer:
Answer:
15, 17, 19
Step-by-step explanation:
x + x+2 + x+4 = 15 + (x+2 + x+4)
3x + 6 = 15 + 2x + 21
x = 15
x+2 = 17
x+4 = 19
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Answer:
y= (5/3) x + 5
Step-by-step explanation:
y = mx + b
m = (5 - 0)/(0 - (-3)) = 5/3
y = (5/3)x + b
b = 0-(5/3)(-3) = 5
y = (5/3)x + 5
Answer:
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Step-by-step explanation:
Answer:

Step-by-step explanation:
you can divide both sides by 2.35 to get the right side to be 1:

You need to multiply the two numbers. Or you can use long addition.
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