Answer:
A. Graph attached
B. It's a function. One input has only one output, it passed the vertical line test.
Step-by-step explanation:
a₀ = 3 a₁ = 6 = 3 x 2¹ a₂ = 6 x 2 = 3 x 2² ..... aₙ = 3 x 2ⁿ
answer graph attached
Find a consecutive odd numbers where the sum of the first three numbers is 15 greater then the final two numbers.
1 answer:
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Alright, lets get started.
A right triangle (triangle 1) has a hypotenuse length of 115 mm and α = 31.2°. What are the measurements for a, b, and β?
Please refer the diagram I have attached.
Using SOH CAH TOA,
Plugging the value of sin 31.2
mm
Similarly,
Plugging the value of cos 31.2
mm
Now, for angle β
tan β =
tan β = 1.65
Using tan inverse
β = 58.78°
So, the answer is a = 98.36 mm, b = 59.57 mm and β = 58.78° : Answer
Hope it will help :)
A right triangle (triangle 1) has measurements of a = 505 mm and b = 286 mm. What are the measurements for c, α, and β?
Please refer the diagram I have attahced.
a and b are given, we could side c by using Pythagorean theorem.
Taking square root on both sides
c = 580.36 mm
Using SOH CAH TOA,
tan α =
taking tan inverse
α = 60.48°
Similarly,
tan β =
taking tan inverse
β = 29.52°
So, the answer is c = 580.36 mm, α = 60.48° and β = 29.52° : Answer
Hope it will help :)
Answer:
Step-by-step explanation:
1.
cot x sec⁴ x = cot x+2 tan x +tan³x
L.H.S = cot x sec⁴x
=cot x (sec²x)²
=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]
= cot x(1+ 2 tan²x +tan⁴x)
=cot x+ 2 cot x tan²x+cot x tan⁴x
=cot x +2 tan x + tan³x [ ∵cot x tan x =1]
=R.H.S
2.
(sin x)(tan x cos x - cot x cos x)=1-2 cos²x
L.H.S =(sin x)(tan x cos x - cot x cos x)
= sin x tan x cos x - sin x cot x cos x
= sin²x -cos²x
=1-cos²x-cos²x
=1-2 cos²x
=R.H.S
3.
1+ sec²x sin²x =sec²x
L.H.S =1+ sec²x sin²x
= [
]
=1+tan²x
=sec²x
=R.H.S
4.
L.H.S=
= 2 csc x
= R.H.S
5.
-tan²x + sec²x=1
L.H.S=-tan²x + sec²x
= sec²x-tan²x
=
=1