Find a consecutive odd numbers where the sum of the first three numbers is 15 greater then the final two numbers.
1 answer:
Answer:
15, 17, 19
Step-by-step explanation:
x + x+2 + x+4 = 15 + (x+2 + x+4)
3x + 6 = 15 + 2x + 21
x = 15
x+2 = 17
x+4 = 19
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