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Vinvika [58]
4 years ago
8

Two locomotives approach each other on parallel tracks. Each has a speed of 87 km/hr with respect to the ground. If they are ini

tially 27 km apart, how long (in minutes) will it be before they reach each other?
Mathematics
1 answer:
sergiy2304 [10]4 years ago
4 0

Answer:

9.3

Step-by-step explanation:

if both travel at same speed they will take equal distance and time to reach the middle and collide.

hence, 27/2 =13.5km

speed=distance/time

time = distance/speed

time= 13.5/87 = 0.15517mm hr

0.15517×60 = 9.31minutes

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Pani-rosa [81]

Answer:

the no of puppets that could be made with his string is 21

Step-by-step explanation:

Given that

There is 7 yards

And, it needs one -third of string for each of his puppets

= 7 × 3

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We simply multiply the 7 yards with the 3 so that the no of puppets could come

hence, the no of puppets that could be made with his string is 21

8 0
3 years ago
It took team rise over run 1 2/3 hours to hike 4 2/3 miles. What is their average speed in miles per hour?
pogonyaev

To find their average miles per hour we can divide the total miles by the hour used:

4 2/3 ÷ 1 2/3

=4x3+2/3 ÷ 1x3+2/3

=14/3 ÷ 5/3

In division, when we switch the place of numerator and denominator, we can change it to multiplication which makes the calculation easier as we can factorize the numbers.

=14/3 x 3/5

Factorize 3 in both amounts:

=14/1 x 5/1

=14/5

=2.8 miles/hour

Therefore their average speed is 2.8 miles/hour.

Hope it helps!

8 0
3 years ago
If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?
Irina18 [472]

Answer:

36

Step-by-step explanation:

Hello,

If X=x^2 it becomes

X^3-289X^2-X+289=(X^2-1)(X-289)

and 289=17^2

X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)

So,

x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)

a = 1

b = 1

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d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

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