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3 years ago

Help me with this geometry questions please (Radom questions will be reported)

Mathematics

1 answer:

stiks02 [169]3 years ago

4 0

I'm not entirely sure about this one, but

A. 40°
B. 100°
C. Idk :P

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Point m is the midpoint of ab¯¯¯¯¯ . am=2x+9, and ab=8x−50. what is the length of am¯¯¯¯¯¯ ?

iogann1982 [59]

Since m is the midpoint of ab, then the following relationship is fulfilled:
$am = \frac{ab}{2}$
Therefore, substituting values we have:
$2x+9 = \frac{8x-50}{2}$
From here, we clear the value of x.
We have then:
$2x+9 = 4x-25$
$9+25 = 4x-2x$
$34 = 2x$
$x = \frac{34}{2}$
$x = 17$
Then, the value of am, is given by substituting x in the expression:
$am=2x+9$
Substituting we have:
$am=2(17)+9$
$am=34+9$
$am=43$
Answer:
the length of am is:
$am=43$

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4 years ago

If ABC is dilated by a scale factor of two with a dilation Center of A, what will be the coordinates of point b

BabaBlast [244]

The answer is (0,6)

move me up to brainliest

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3 years ago

A diver needs to descend to a depth of 100 feet. She wants to do it in 5 equal descendants. How far should she travel in each de

Sergio039 [100]

She should travel 100/5 = 20 feet in each descent.

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3 years ago

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What is the 25% of 500

Ulleksa [173]

Answer:

Step-by-step explanation:

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3 years ago

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Answer the following questions. a. In the general education course requirement at a college, a student needs to choose one each

Bezzdna [24]

Answer:

a) N = 240 ways

b) N = 303,600 ways

c) N = 10 ways

Step-by-step explanation:

a) Given

General course consist of one course from each of 4 groups.

Social Science = 5 options

Humanities = 4 options

Natural sciences = 4 options

Foreign language = 3 options.

Therefore the total number of possible ways of selecting one each from each of the 4 groups is:

N = 5×4×4×3 = 240 ways

b) if four people are chosen from 25 member for four different positions, that makes it a permutation problem because order of selection is important.

N = nPr = n!/(n-r)!

n = 25 and r = 4

N = 25P4 = 25!/(25-4)! = 25!/21!

N = 303,600 ways

c) The number of ways by which 5 tosses of coin can yield 2 heads and 3 tails.

N = 5!/(5-5)!(2!)(3!)

N = 5×4/2

N = 10 ways

7 0

3 years ago