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jenyasd209 [6]
3 years ago
15

Sydney wants to explain the concept of the axial and appendicular skeleton.if she uses an analogy of a coat rack,what would the

different parts of the picture represent
Biology
2 answers:
stealth61 [152]3 years ago
5 0

The area residing in the center explains the bilatial tibulti, which precedents the bratuluti tubilitu. As for the rack itself, it has a half-moon (in laymens terms) axial, which appendages smoothly in all transition. The answer would certainty relate less to moving and a part itself, and more towards coordination or other terms (for which there are many), as this question is quite subjective.

In short, it has nearly free half-moon movement, though blocked in transition by its own quartsor axial.

Semenov [28]3 years ago
3 0

Answer:

The correct answer will be-

1. axial skeleton-the central pole

2. appendicular skeleton- the side pipes

Explanation:

The skeletal system of humans is categorized into two types: the appendicular skeleton and the axial and skeleton. The axial skeleton is made up of the central axis of the human body which is made  

of the skull spine and ribs whereas the appendicular skeleton system forms the skeletal system surrounding the central axial system which is composed of both the lower and upper limbs.

If this skeleton system is compared to the coat rack then the central pole or pipe will be considered the axial skeleton while the side pipes on both the sides will be considered the appendicular skeleton.  

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How many possible open reading frames (frames without stop codons) are there that extend through the following sequence? 5'... C
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Answer:

There are 4 reading frames without stop codons.

Explanation:

1) To find the possible reading frames you need to separate your sequence in codons (trios)  for the 5'-> 3' sense, first, excluding the first nucleotide, then excluding 2 nucleotides and then not excluding nucleotides.

5'... C TTA CAG TTT ATT GAT ACG GAG AAG G... 3'  NO STOP CODON

5'... CT TAC AGT TTA TTG ATA CGG AGA AGG... 3'  NO STOP CODON

5'... CTT ACA GTT TAT <u>TGA</u> TAC GGA GAA GG... 3'

2)Then you find the complementary sequence (which you already have)

3'... GAA TGT CAA ATA ACT ATG CCT CTT CC... 5'

3'... GA ATG TCA AAT AAC TAT GCC TCT TCC... 5'

3'... G AAT GTC AAA TAA CTA TGC CTC TTC C... 5'

3) Next, you have to obtain the reverse complementary

CCT TCT CCG TAT CAA TAA ACT GTA AG NO STOP CODON

CC TTC TCC GTA TCA ATA AAC TGT AAG NO STOP CODON

C CTT CTC CGT ATC AAT AAA CTG <u>TAA</u> G

4)Now you need to find start (AGT in terms of DNA) and stop codons(<u>TAA</u>, <u>TAG,</u> <u>TGA</u>, also in terms of DNA), in 5->3 and de reverse complementary.

<em />

<em>As you can see, you have for open reading frames that lack of stop codon, unfortunately, they also lack of AGT, the start codon.</em>

I added a table where you can find thestart and stop codons as well as the proteins that they translate to in terms of RNA.

I hope you find this information interesting and useful, good luck!

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Explanation:

Hope it helps :)

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