Sweat glands sorry if im wrong not sure
Answer:
A) 0.1 a, 0.9 A
Explanation:
According to the given information, all the individuals in the founder population had free earlobes. Since the allele for the free earlobes (A) is dominant over the one for the attached earlobes (a), the genotype of each of the homozygous dominant founder individual would be "AA". Humans are diploid and one individual has two alleles for each gene in its genome. Total number of alleles for the earlobe in the founder population = 10 x 2 = 20.
Frequency of dominant allele, A in the founder population = total number of homozygous dominant individuals x 2 + the total number of heterozygous genotype / total alleles for the earlobe in the population. There were 8 homozygous dominant and 2 heterozygous dominant individuals in the population.
So, frequency of dominant allele = 8 x 2 + 2 / 20 = 16 + 2 / 20 = 18/20 = 0.9
Since p+q=1; frequency of recessive allele "a" = 1-p = 1-0.9 = 0.1
