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DanielleElmas [232]
3 years ago
15

(10%) Problem 10: A 7.25-kg bowling ball moving at 9.85 m/s collides with a 0.875-kg bowling pin, which is scattered at an angle

of θ = 21.5° from the initial direction of the bowling ball, with a speed of 10.5 m/s.
Physics
1 answer:
siniylev [52]3 years ago
5 0

Answer

given,

mass of bowling ball = 7.25 Kg

moving speed of the bowling ball = 9.85 m/s

mass of bowling in = 0.875 Kg

scattered at an angle = θ = 21.5°

speed after the collision = 10.5 m/s

angle of the bowling ball

tan \theta_1 = \dfrac{-[m_2v_2Sin \theta_2]}{m_1v_1 - (m_2v_2cos \theta_2)}

tan \theta_1 = \dfrac{-[0.875\times 10.5 \times Sin 21.5^0]}{7.25\times 9.85 - (0.875\times 10.5 \times cos 21.5^0)}

tan \theta_1 = \dfrac{-[3.3672]}{62.86}

tan \theta_1 = 0.0536

\theta_1 =-3.066^0

b) magnitude of final velocity

v = \dfrac{-m_2v_2sin\theta_2}{m_1 sin\theta_1}

v = \dfrac{-0.875 \times 10.5 sin21.5^0}{7.25 sin(-3.066^0)}

v = 8.68 m/s

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False it never decreases, it increases or remain the same.


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3 years ago
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He drives 150 meters in 18 seconds. Assuming constant speed, what is his speed in meters per second?
ira [324]

Answer:

Explanation:

Givens

d = 150 meters

t  = 18 seconds

r (rate) = ?

Formula

r = d/t

Solution

r = 150/18

r = 8.33 m/s

4 0
3 years ago
Two identical objects, A and B, are sitting on a table. If the net force on object A is 5 N and the net force on object B is 10
sveta [45]

If the net force on object A is 5 N and the net force on object B is 10 N, then object B will accelerate more quickly than object A provided the mass of both objects are same.

Answer: Option C

<u>Explanation: </u>

According to Newton’s second law of motion, any external force applied on an object is directly proportional to the mass and acceleration of the object. In order to state this law in terms of acceleration, it is stated that acceleration exhibited by any object is directly proportional to the net force applied on the object and inversely proportional to the mass of the object as shown below:

                      \text {Acceleration of the object } \propto \frac{\text {Net force on the object}}{\text {Mass of the object}}

So if two objects A and B are identical which means they have same mass, then the acceleration attained by the object will be directly proportionate to the net forces exerted on the objects only.

Thus if the force applied is more for one object, then the object will be exhibiting more acceleration compared to the other one. So as object B is experiencing a net force of 10 N which is greater than the net force experiences by object A, then the object B will be accelerating more quickly compared to the object A's acceleration.

7 0
3 years ago
Si aplicamos una fuerza constante de 30 N sobre un cuerpo de 25 Kg, este se mueve de tal manera que en 5 s adquiere la velocidad
Ganezh [65]

Answer:

<em>Si hay rozamiento y el valor de la fuerza de roce es 10 N</em>

Explanation:

<u>Fuerza Neta</u>

La fuerza neta sobre un cuerpo es la suma vectorial de todas las fuerzas actuantes sobre el mismo.

Si conocemos el módulo de la fuerza neta F y la masa m del cuerpo, aplicamos la segunda ley de Newton para relacionarlas con la aceleración a:

F=m.a

Tenemos los datos cinemáticos de la situación, según la cual el cuerpo adquiere una velocidad (desde el reposo) de 4 m/s en 5 s.

Utilizamos la fórmula:

v_f=v_o+a.t

Y despejamos la aceleración:

\displaystyle a=\frac{v_f-v_o}{t}

\displaystyle a=\frac{4-0}{5}

a=0.8 \ m/s^2

Podemos calcular la aceleración real que el cuerpo adquiere, producto de una fuerza efectiva igual a:

F_e=25\ Kg\cdot 0.8 \ m/s^2

F_e=20\ N

Si se está aplicando una fuerza de F_a= 30 N y solo 20 N producen movimiento, entonces se está perdiendo en rozamiento una fuerza:

F_r=F_a-F_e=30 - 20=10

F_r=10\ N

Si hay rozamiento y el valor de la fuerza de roce es 10 N

8 0
3 years ago
In which of these situations, is mechanical energy being conserved? (Neglect, air resistance, friction, and breaking) Check all
lana66690 [7]

1) Mechanical energy is conserved in all the situations listed

2) True

3) The energy that an object has stored due to its position or shape is called potential energy

4) The potential energy of the block is 490 J

5) The potential energy of the elevator is 750,000 J

Explanation:

1)

The mechanical energy of an object is the sum of its kinetic energy (KE) and its potential energy (PE):

E=KE+PE

Where

KE is the energy due to the motion of the object

PE is the energy due to the position of the object (it can be either gravitational potential energy or elastic potential energy)

In absence of non-conservative forces, such as friction or air resistance, the mechanical energy is always conserved. Therefore, the mechanical energy is conserved in all the situations listed here:

Child on a swing  --> there is a continuous conversion between gravitational potential energy and kinetic energy

Pendulum  --> there is a continuous conversion between gravitational potential energy and kinetic energy

Bow and Arrow  --> there is a conversion between elastic potential energy of the bow and kinetic energy of the  arrow

Roller Coaster --> there is a continuous conversion between gravitational potential energy and kinetic energy

2)

The potential energy of an object is given by

PE=mgh

where

m is its mass

g is the acceleration due to gravity

h is the height of the object relative to the ground

While the kinetic energy is given by

KE=\frac{1}{2}mv^2

where

v is the speed of the object

As an object falls to the ground, its height h decreases, therefore the potential energy PE decreases as well. However, the speed of the object, v, increases during the fall, and therefore the kinetic energy KE increases. This means that potential energy is converted into kinetic energy.

3)

Potential energy is the energy possessed by an object due to its position. It can be of two types:

  • Gravitational potential energy: it is the potential energy due to the position of an object in a gravitational field. It is calculated as mgh, as shown in part 2)
  • Elastic potential energy: it is the potential energy stored in an elastic object when it is stretched or compressed. It is calculated as \frac{1}{2}kx^2, where k is the spring constant of the elastic object and x is the stretching/compression of the object relative to its equilibrium position.

4)

The potential energy stored in an object held above the ground is given by

PE=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object relative to the ground

For the object in this problem, we have

m = 10 kg

g=9.8 m/s^2

h = 5 m

Substituting, we find

PE=(10)(9.8)(5)=490 J

5)

As before, the potential energy of the elevator is given by

PE=mgh

where m is its mass and h is its height above the ground.

Here we don't have the mass of the elevator. However, we know its weight:

W=1500 N

But we also know that the weight of an object is equal to the product between its mass and the acceleration of gravity:

W=mg

So we can rewrite the potential energy as

PE=Wh

and the height of the elevator is

h = 500 m

Therefore, its potential energy is

PE=(1500)(500)=750,000 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

5 0
3 years ago
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