Answer: 9.9%
Explanation: efficiency = (work output /work input) × 100
Note that, 1 kilocalorie = 4184 joules, hence 22kcal = 22× 4184 = 92048 joules.
Work output = 9200 j and work input = 92048 j
Efficiency = (9200/92048) × 100 = 0.099 × 100 = 9.9%
1. B
2. A
3. B
4. C
5. heterogeneous
6. element
7. do
8. true
9. true
10. true
Answer:
the unit of velocity is meter per second
The net force performs a total amount of work equal to
(45 N) (0.80 m) = 36 J
on the bullet, and this is in turn is equal to the change in the bullet's kinetic energy by the work-energy theorem. So we have
W = ∆K = 1/2 mv²
since the bullet starts at rest, where m = its mass and v = its final velocity.
Solve for v :
36 J = 1/2 (0.0050 kg) v² ⇒ v = 120 m/s