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3 years ago

In the formula used to solve problems related to the first law of thermodynamics, what does Q represent? A.internal energy

Physics

2 answers:

DENIUS [597]3 years ago

8 0

Answer:

B.heat

Explanation:

As we know by First law of thermodynamics

$Q = \Delta U + W$

as we know that

Q = heat or thermal energy supplied to the system

$\Delta U$ = change in internal energy of the system

W = work done by the system

So first law of thermodynamics is basically energy conservation law in which energy supplied to the system is converted into its internal energy and work done by the system.

Blizzard [7]3 years ago

7 0

B, heat, is the correct answer. Heat is represented by a capital q in thermodynamic equations.

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gulaghasi [49]

Answer:

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Explanation:

If there is 1 Circuit and it runs out of energy, there's another one to produce the power.

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A block of mass 27.00 kg sits on a horizontal surface with, coefficient of kinetic

zhannawk [14.2K]

Answer:

The force is $F = 172 \ N$

Explanation:

From the question we are told that

The mass of the block is $m_b = 27.0 \ kg$

The coefficient of static friction is $\mu_s = 0.65$

The coefficient of kinetic friction is $\mu_k = 0.50$

The normal force acting on the block is

$N = m * g$

substituting values

$N = 27 * 9.8$

$N = 294.6 \ N$

Given that the force we are to find is the force required to get the block to start moving then the force acting against this force is the static frictional force which is mathematically evaluated as

$F_f = \mu_s * N$

substituting values

$F_f = 0.65 * 264.6$

$F_f = 172 \ N$

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3 years ago

Given Vout = 17.33 vpp and R1 = 3 kΩ, find the value of RF required to provide Av = 4.33. (Round your answer to 2 decimal places

Olenka [21]

Answer:

The magnitude of $V_{2}$ is 4 V and phase of input voltage is zero

Explanation:

Given:

Output voltage $V_{out} = 17.33$

Resistance $R_{1} = 3$ kΩ

Voltage gain $A_{v} = 4.33$

For finding feedback resistance we use gain equation

Gain equation for non inverting op-amp is given by,

$A_{v} = 1+\frac{R_{f} }{R_{1} }$

$4.33 = 1+ \frac{R_{f} }{3 k }$

$R_{f}$ ≅ 10 kΩ

For finding input voltage we use,

$A_{v} = \frac{V_{out} }{V_{2} }$

$V_{2} = \frac{17.33}{4.33}$

$V_{2} = 4$ V

The Phase of $V_{2}$ is zero because output voltage phase is 360°

Therefore, the magnitude of $V_{2}$ is 4 V and phase of input voltage is zero

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3 years ago

How do you find velocity when given 3 numbers

forsale [732]

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3 years ago