Answer: B
Explanation: the wave with the largest amplitude would create ththe loudest sound, and based on the picture provided, I would guess B has the largest amplitude.
Answer:
B.The linear velocity of the gears is the same. The linear velocity is 432π centimeters per minute.
Explanation:
As we know that the small gear completes 24 revolutions in 20 seconds
so the angular speed of the smaller gear is given as


Now we know that the tangential speed of the chain is given as

so we have



Since both gears are connected by same chain so both have same linear speed and hence correct answer will be
B.The linear velocity of the gears is the same. The linear velocity is 432π centimeters per minute.
Answer:
U = √Rg/sin2θ
Explanation:
Using the formula for "range" in projectile motion to derive the average speed before the ball hits the ground.
Range is the distance covered by the body in the horizontal direction from the point of launch to the point of landing.
According to the range formula,
R = U²sin2θ/g
Cross multiplying we have;
Rg = U²sin2θ
Dividing both sides by sin2θ, we have;
U² = Rg/sin2θ
Taking the square root of both sides we have;
√U² = √Rg/sin2θ
U = √Rg/sin2θ
Therefore, his average speed if he is to meet the ball just before it hits the ground is √Rg/sin2θ
- Mass of the diver (m) = 90 Kg.
- Height of the board from the ground (h) = 10 m.
- Acceleration due to gravity (g) = 9.8 m/s^2.
- Height of the diver from the ground when he reaches point C (x) = 5m
- Initial velocity (u) = 0 m/s
- We know, gravitational potential energy of a body = mass × acceleration due to gravity × height.
- Therefore, the gravitational potential energy of the diver when he reaches point C (GPE) = mg(h - x)
- or, GPE = [90 × 9.8 × (10-5)] J
- or, GPE = [90 × 9.8 × 5] J
- or, GPE = 4410 J
- For a freely falling body,
- v^2 - u^2 = 2gh
- or, v^2 = 2gh
- We know, kinetic energy of a body = 1/2 mv^2
- Therefore, kinetic energy of the diver when he reaches point C (KE) = 1/2 m(2gx)
- Here, 2gx = (2 × 9.8 × 5) = 98 (m/s)^2
- We have already seen v^2 = 2gh
- or, v = √2gh
- So, the velocity of the diver = √2gx = √98 m/s = 9.9 m/s
<u>Answers:</u>
<em><u>The </u></em><em><u>gravitational</u></em><em><u> potential</u></em><em><u> energy</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>diver </u></em><em><u>when </u></em><em><u>he</u></em><em><u> reaches</u></em><em><u> point</u></em><em><u> C</u></em><em><u> </u></em><em><u>is </u></em><em><u>4</u></em><em><u>4</u></em><em><u>1</u></em><em><u>0</u></em><em><u> </u></em><em><u>J.</u></em>
<em><u>The </u></em><em><u>velocity</u></em><em><u> </u></em><em><u>of </u></em><em><u>the </u></em><em><u>diver </u></em><em><u>is </u></em><em><u>9</u></em><em><u>.</u></em><em><u>9</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer: 4.5 hours to a minutes would be 270 minutes. I hope this helped you god bless you and have a great day :D