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Daniel [21]
3 years ago
9

An object that starts at a position of 5 m and travels for 3 seconds at a velocity of -9 m/s ends up at what position?

Physics
1 answer:
Rina8888 [55]3 years ago
5 0

Answer:

Sorry don't know the answer

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Which of the following waves would produce the loudest sound?
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Answer: B

Explanation: the wave with the largest amplitude would create ththe loudest sound, and based on the picture provided, I would guess B has the largest amplitude.

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2 years ago
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Two wheel gears are connected by a chain. The larger gear has a radius of 8 centimeters and the smaller gear has a radius of 3 c
dezoksy [38]

Answer:

B.The linear velocity of the gears is the same. The linear velocity is 432π centimeters per minute.

Explanation:

As we know that the small gear completes 24 revolutions in 20 seconds

so the angular speed of the smaller gear is given as

\omega = 2\pi\frac{24}{20}

\omega = 2.4\pi rad/s

Now we know that the tangential speed of the chain is given as

v = r \omega

so we have

v = (3 cm)(2.4\pi)

v = 7.2 \pi cm/s

v = 432\pi cm/min

Since both gears are connected by same chain so both have same linear speed and hence correct answer will be

B.The linear velocity of the gears is the same. The linear velocity is 432π centimeters per minute.

8 0
4 years ago
A soccer ball is kicked from the ground with an initial speed v at an upward angle θ. A player a distance d away in the directio
LuckyWell [14K]

Answer:

U = √Rg/sin2θ

Explanation:

Using the formula for "range" in projectile motion to derive the average speed before the ball hits the ground.

Range is the distance covered by the body in the horizontal direction from the point of launch to the point of landing.

According to the range formula,

R = U²sin2θ/g

Cross multiplying we have;

Rg = U²sin2θ

Dividing both sides by sin2θ, we have;

U² = Rg/sin2θ

Taking the square root of both sides we have;

√U² = √Rg/sin2θ

U = √Rg/sin2θ

Therefore, his average speed if he is to meet the ball just before it hits the ground is √Rg/sin2θ

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3 years ago
A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energ
skad [1K]
  • Mass of the diver (m) = 90 Kg.
  • Height of the board from the ground (h) = 10 m.
  • Acceleration due to gravity (g) = 9.8 m/s^2.
  • Height of the diver from the ground when he reaches point C (x) = 5m
  • Initial velocity (u) = 0 m/s
  • We know, gravitational potential energy of a body = mass × acceleration due to gravity × height.
  • Therefore, the gravitational potential energy of the diver when he reaches point C (GPE) = mg(h - x)
  • or, GPE = [90 × 9.8 × (10-5)] J
  • or, GPE = [90 × 9.8 × 5] J
  • or, GPE = 4410 J
  • For a freely falling body,
  • v^2 - u^2 = 2gh
  • or, v^2 = 2gh
  • We know, kinetic energy of a body = 1/2 mv^2
  • Therefore, kinetic energy of the diver when he reaches point C (KE) = 1/2 m(2gx)
  • Here, 2gx = (2 × 9.8 × 5) = 98 (m/s)^2
  • We have already seen v^2 = 2gh
  • or, v = √2gh
  • So, the velocity of the diver = √2gx = √98 m/s = 9.9 m/s

<u>Answers:</u>

<em><u>The </u></em><em><u>gravitational</u></em><em><u> potential</u></em><em><u> energy</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>diver </u></em><em><u>when </u></em><em><u>he</u></em><em><u> reaches</u></em><em><u> point</u></em><em><u> C</u></em><em><u> </u></em><em><u>is </u></em><em><u>4</u></em><em><u>4</u></em><em><u>1</u></em><em><u>0</u></em><em><u> </u></em><em><u>J.</u></em>

<em><u>The </u></em><em><u>velocity</u></em><em><u> </u></em><em><u>of </u></em><em><u>the </u></em><em><u>diver </u></em><em><u>is </u></em><em><u>9</u></em><em><u>.</u></em><em><u>9</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

5 0
2 years ago
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Convertir 4.5 hr a min
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Answer: 4.5 hours to a minutes would be 270 minutes. I hope this helped you god bless you and have a great day :D

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4 years ago
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