Answer:
h = 31.9 m
Explanation:
Since, the ball took 5.1 s in the air. Hence, the time to reach maximum height will be equal to the half of this value:
t = 5.1 s /2 = 2.55 s
Now, we use 1st equation of motion between the time of throwing and the time of reaching maximum height:
Vf = Vi + gt
where,
Vf = Final Velocity = 0 m/s (since, ball momentarily stops at highest point)
Vi = Initial Velocity = ?
g = - 9.8 m/s² (negative sign for upward motion)
Therefore,
0 m/s = Vi + (-9.8 m/s²)(2.55 s)
Vi = 24.99 m/s
Now, we use second equation of motion for height (h):
h = Vi t + (0.5)gt²
h = (24.99 m/s)(2.55 s) + (0.5)(-9.8 m/s²)(2.55 s)²
h = 63.7 m - 31.8 m
<u>h = 31.9 m</u>
Answer:
Linear charge density (I) = Q/2πR
Explanation:
Linear charge density (I) = charge (Q) per unit length(L)
I = Q/L
For a thin ring of charge with radius R, the length will be equal to the circumference of a circle.
Circumference of a circle = 2πR
Then, the length of the thin ring of charge is 2πR
Linear charge density (I) = Q/2πR
Therefore, for a thin ring of charge of radius R, which lies in the x-y plane and is centered on the z-axis. The linear charge density, l, of the loop is given by Q/2πR
It depends on what robots are in our future. Robots could even be the future.
Answer:
Explanation:
Given that,
The mass of the Jupiter,
The radius of Jupiter,
We need to find the acceleration due to gravity on Jupiter. The formula is
Put all the values,
So, the value of acceleration due to gravity on the Jupiter is 
.
Considering Conservation of Momentum, the momentum
before and after must remain the same:
so:
before:
