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malfutka [58]
3 years ago
13

Two waves meet and overlap. The first wave has an amplitude of 4.6 centimeters and the second wave has an amplitude of 2 centime

ters. If the waves meet crest to trough, what is the magnitude of the resulting amplitude of the combined wave?
Physics
1 answer:
vodka [1.7K]3 years ago
3 0

Answer:

Explanation:

The amplitude of resultant wave as the result of  overlap of two waves depends upon the phase difference between the two.  If the waves meet crest to trough , the phase difference is 180 degree or they are in opposite phase . Hence they will destroy each other . The amplitude of resultant wave can be obtained by subtracting the amplitudes of two waves. They will interfere destructively.

Amplitude of resultant gives waves = 4.6 - 2 = 2.6 cm.

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Large electric fields in cell membranes cause ions to move through the cell wall. The field strength in a typical membrane is 1.
jeka57 [31]

Answer:

1.6\cdot 10^{-12}N

Explanation:

The electric force on a charged particle is given by

F=qE

where

q is the charge of the particle

E is the strength of the electric field

In this problem, we have

E=1.0\cdot 10^7 N/C is the electric field strength

q=+e=+1.6\cdot 10^{-19}C is the charge of the calcium ion

Therefore, the electric force exerted on the calcium ion is

F=(1.6\cdot 10^{-19}C)(1.0\cdot 10^7 N/C)=1.6\cdot 10^{-12}N

5 0
3 years ago
A person runs up several flights of stairs and is exhausted at the top. Later the same person walks up the same stairs and does
KIM [24]

Answer:

Explanation:

Work done by the person depends on its mass and the height raised. It also depends on the acceleration due to gravity.

As the height raised and the mass of person is same. The value of acceleration due to gravity is also constant So, the work done is also same in both the cases.

6 0
3 years ago
Derive equation of motion s=ut+1/2at²​
Pavel [41]

Recall the definitions of

• average velocity:

v[ave] = ∆x/∆t = (x[final] - x[initial])/t

Take the initial position to be the origin, so x[initial] = 0, and we simply write x[final] = s. So

v[ave] = s/t

• average acceleration:

a[ave] = ∆v/∆t = (v[final] - v[initial])/t

Assume acceleration is constant (a[ave] = a). Let v[initial] = u and v[final] = v, so that

a = (v - u)/t

Under constant acceleration, the average velocity is also given by

v[ave] = (v[final] + v[initial])/2 = (v + u)/2

Then

v[ave] = s/t = (v + u)/2   ⇒   s = (v + u) t/2

and

a = (v - u)/t   ⇒   v = u + at

so that

s = ((u + at) + u) t/2

s = (2u + at) t/2

s = ut + 1/2 at²

4 0
2 years ago
7. If the impact of the golf club on the ball in the previous question occurs over a time of 2 x 10 seconds, what
Kruka [31]

Answer:

3.65 x mass

Explanation:

Given parameters:

Time  = 20s

Initial velocity  = 0m/s

Final velocity  = 73m/s

Unknown:

Force the ball experience  = ?

Solution:

To solve this problem, we apply the equation from newton's second law of motion:

    F  =  m \frac{v  - u}{t}  

m is the mass

v is the final velocity

u is the initial velocity

 t is the time taken

So;

  F  = m (\frac{73 - 0}{20} )  = 3.65 x mass

4 0
3 years ago
What is the smallest value of n for which the wavelength of a Balmer series line is less than 400 nm
Natasha_Volkova [10]

Answer:

The smallest value is n= 2

Explanation:

The balmer equation is given below

1/λ = R(1/4 - 1/n₂²).

R= 1.0973731568508 × 10^7 m^-1

λ= 400*10^-9 m

(400*10^-9)= 1.0973731568508 × 10^7 (1/4-1/n²)

(400*10^-9)/1.0973731568508 × 10^7

= 1/4 - 1/n²

364.51 *10^-16= 1/4 - 1/n²

1/n²= 1/4 -364.51 *10^-16

1/n² = 0.25-3.6451*10^-14

1/0.25= n²

4= n²

√4= n

2= n

The smallest value is N= 2

7 0
3 years ago
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