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jeyben [28]
3 years ago
10

What does stoichiometry use to relate moles of one molecule to moles of another?

Chemistry
1 answer:
klio [65]3 years ago
6 0

Answer:

The answer is B

Explanation:

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Which of the following is a mixture?<br><br> steel<br> water<br> oxygen<br> gold
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Steel because it is a physical combination of different metals.
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3 years ago
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An example of a chemical change is burning a wood log to give a pile of ashes.<br> O True O False
serious [3.7K]

Answer:

True

Explanation:

<em>An example of a chemical change is burning a wood log to give a pile of ashes.</em> TRUE. In a chemical change there is a change in the identity of the substances, that is, some substances react (reactants) in order to form other substances (products).

A wood log is made of cellulose and organic compound that react with oxygen to produce carbon dioxide and water mainly.

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3 years ago
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Provide the most likely dominant bonding mechanism in the following solid compounds:a.CaO b. InAs c. Al2O3 d.Bronze
padilas [110]

Answer:

CaO- ionic

InAs-covalent

Al2O3-ionic

Bronze- metallic

Explanation:

CaO and Al2O3 are mostly ionic even though the posses a little covalent character but ionic bonding is the main bonding scheme. Bronze is an alloy of two metals hence it contains a metallic bond. InAs has an electro negativity difference of 0.4 between the atoms so it is a polar covalent bond.

5 0
4 years ago
A 1.00 l solution contains 3.50×10-4 m cu(no3)2 and 1.75×10-3 m ethylenediamine (en). the kf for cu(en)22+ is 1.00×1020. what is
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<span>Answer: A 1.00 L solution containing 3.00x10^-4 M Cu(NO3)2 and 2.40x10^-3 M ethylenediamine (en). contains 0.000300 moles of Cu(NO3)2 and 0.00240 moles of ethylenediamine by the formula Cu(en)2^2+ 0.000300 moles of Cu(NO3)2 reacts with twice as many moles of en = 0.000600 mol of en so, 0.00240 moles of ethylenediamine - 0.000600 mol of en reacted = 0.00180 mol en remains by the formula Cu(en)2^2+ 0.000300 moles of Cu(NO3)2 reacts to form an equal 0.000300 moles of Cu(en)2^2+ Kf for Cu(en)2^2+ is 1x10^20. so 1 Cu+2 & 2 en --> Cu(en)2^2+ Kf = [Cu(en)2^2+] / [Cu+2] [en]^2 1x10^20. = [0.000300] / [Cu+2] [0.00180 ]^2 [Cu+2] = [0.000300] / (1x10^20) (3.24 e-6) Cu+2 = 9.26 e-19 Molar since your Kf has only 1 sig fig, you might be expected to round that off to 9 X 10^-19 Molar Cu+2</span>
4 0
3 years ago
Whose work directly resulted in the development of and atomic model that has negative electrons stuck within a sea of positive m
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