Answer:
which app are u using u should use Android studio or if u are using mac book use xcode
Answer:
Latency of an object O is shown below.
Explanation:
W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R
latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]
After combining the two case
latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]
where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.
server time for transmit the object is (K-1)[S/R +RTT - WS/R]
A(n) BI server produces dynamic reports, supports alerts/RSS functionality, and supports user subscriptions.
<h3>What exactly is BI server?</h3>
An on-premises report server with a web gateway, Power BI Report Server allows you to see and manage reports and KPIs. The tools for generating Power BI reports, paginated reports, mobile reports, and KPIs are also included. A business intelligence server created by Oracle is called Oracle Business Intelligence Enterprise Edition. It has sophisticated business intelligence capabilities that are based on a single architecture. The server offers centralized data access to all corporate entity-related business information.
There are five stages to query compilation in BI server:
- Parsing
- Create Logical Requests
- Navigation
- Code Generation Rewrite
To learn more about BI server , refer to:
brainly.com/question/7601044
#SPJ4
Answer:
Explanation:
The following code is written in Java. It creates the raiseToPower method that takes in two int parameters. It then uses recursion to calculate the value of the first parameter raised to the power of the second parameter. Three test cases have been provided in the main method of the program and the output can be seen in the attached image below.
class Brainly {
public static void main(String[] args) {
System.out.println("Base 5, Exponent 3: " + raiseToPower(5,3));
System.out.println("Base 2, Exponent 7: " + raiseToPower(2,7));
System.out.println("Base 5, Exponent 9: " + raiseToPower(5,9));
}
public static int raiseToPower(int base, int exponent) {
if (exponent == 0) {
return 1;
} else if (exponent == 1) {
return base;
} else {
return (base * raiseToPower(base, exponent-1));
}
}
}
<span>All the terms are adjectives, not names of air masses. But among the adjectives, tepid seems to be the odd one out.</span>