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horsena [70]
4 years ago
14

Write an expression to show y greater than 7, subtracted from 14.​

Mathematics
1 answer:
borishaifa [10]4 years ago
7 0

Answer:

14-(y>7)

Step-by-step explanation:

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Question 12 onlyyyyyyyy
netineya [11]
For number 12 you need to make an expression using the information given. a) 25g + 18r + 15b could be the expression.
b) The variables would be 25g for the 25 gold seats, 18r for the 18 red seats and 15b for the 15 blue seats. 
c) Plug in the number given according to the variables.
       25(100) + 18(250) + 15(200)
             2500 + 4500 + 3000
                   7000 + 3000
                        $10,000
5 0
3 years ago
Write a statement relating the opposites of each of the given numbers.
Leokris [45]
Yes -1/5 is less than 1/3
8 0
4 years ago
Read 2 more answers
The stock of Company A gained $1.86 throughout the day and ended at a value of $94.86. By what percentage did the stock rise
Firlakuza [10]

Answer:

tTe answer is 1.96%

Step-by-step explanation:

given data

change in price/gain= $1.86

the closing price = $94.86

Required.

The percent rise.

Step two:

The formula for the percent rise is

=change/close price*100

substitute our given data

= 1.86/94.86*100

=0.0196*100

=1.96%

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%7D%20%20%3D%20%7B27%7D%5E%7B%3F%7D%20" id="TexFormula1" title=" \sqrt{3} = {27
marishachu [46]

Let the unknown be x


\sqrt{3}  = 27^x


3^\frac{1}{2}  = 3^{3x}


Both the base number are 3, so we equate the exponent:


\dfrac{1}{2}  = 3x


x = \dfrac{1}{2}  \div 3


x = \dfrac{1}{2}  \times \dfrac{1}{3}


x = \dfrac{1}{6}


Answer: 1/6


3 0
3 years ago
Find the solution to the system of equations.<br> 1 + 3y = 4<br> 2r + 5y = 12
ivann1987 [24]

Answer: {x,y}={-1,2}

step-by-step explanation:

// Solve equation [2] for the variable  x

 [2]    2x = 5y - 12

 [2]    x = 5y/2 - 6

// Plug this in for variable  x  in equation [1]

  [1]    2•(5y/2-6) + 3y = 4

  [1]    8y = 16

// Solve equation [1] for the variable  y

  [1]    8y = 16

  [1]    y = 2

// By now we know this much :

   x = 5y/2-6

   y = 2

// Use the  y  value to solve for  x

   x = (5/2)(2)-6 = -1

Solution :

{x,y} = {-1,2}

5 0
3 years ago
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