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2 years ago

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SOLVE. 1/5x=-10

- 10" alt="1 \div 5x = - 10" align="absmiddle" class="latex-formula">

1 answer:

Sladkaya [172]2 years ago

7 0

Answer: X = -50

Step-by-step explanation:

1. 1/5x = -10

1/5x = -10

2.Multiply by 1

3.Multiply all terms by the same value to eliminate fraction denominators.

4.Simplfiy

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Translate to an equation and sole: The quotient of h and 26 is -52

rusak2 [61]

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3 years ago

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Therefore, The conversion of unit is $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

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2 years ago

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ruslelena [56]

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u=9 is your answer.
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2 years ago

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Paraphin [41]

Answer:

Step-by-step explanation:

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2 years ago

What error was made?<br><br> -4(6 - b) = 4<br> -24 - 4b = 4<br> -4b = 28<br> b = -7

lisov135 [29]

Answer:

step 2; a negative times a negative = a positive.

Step-by-step explanation:

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2 years ago